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3 years ago

I need help plz!!!!!?

Mathematics

2 answers:

Simora [160]3 years ago

8 0

What is the question asking..?

Allushta [10]3 years ago

8 0

A. the independent variable is the time and the dependent variable is the snow increasing (independent was most likely repeated here as a mistake)

b. make a table

c. the unit rate is .2/1

d. the unit rate or rate of change represents that the snow increases .2 centimeters in depth every 1 hour.

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X−8≥4 x=? please explain how you got the answer

aev [14]

Answer:

$x \geqslant 12$

Step-by-step explanation:

$x - 8 \geqslant 4$

Move the constant to the right-hand side and change its sign

$x \geqslant 4 + 8$

Add the numbers

$x \geqslant 12$

Alternate form

x∈[12 , + ∞》

5 0

3 years ago

1. Calculate the H.C.F of a 2 b 5 and a 3 b 3 .

harkovskaia [24]

Answer:

Step-by-step explanation:

Problem is HCF:

Of;

a²b⁵ and a³b³

The highest common factor, HCF is used to factor expressions in order to simplify them.

H.C.F is a factor that is common to both expressions.

here we have

a²b⁵ and a³b³

a²b⁵ = a x a x b x b x b x b x b

a³b³ = a x a x a x b x b x b

In both expressions, for a:

a x a and b x b x b x b x b

a x a x a and b x b x b

common factors are a and b

both entities contains a and b

Highest common factor H.CF;

a² and b³

this makes a²b³

a²b³ is common to both of them and it is the highest term that can be factored from the the two.

5 0

4 years ago

Would You RATHER...

nekit [7.7K]

Question really depends on the persons mindset wether he/she likes to be rich or a middle person.

4 0

4 years ago

(3y^0 x^2)^6 times y^-3 zx8

timurjin [86]

Ok so some basic rules

$(x^m)(x^n)=x^{m+n}$
$(ab)^c=(a^c)(b^c)$
$(x^m)^n=x^{mn}$
$x^0=1$
$x^{-m}= \frac{1}{x^m}$

so
$[(3y^0x^2)^6][y^{-3}zx^8]$
$[(3(1)x^2)^6][y^{-3}zx^8]$
$[(3x^2)^6][y^{-3}zx^8]$
$[(3^6)((x^2)^6)][y^{-3}zx^8]$
$[(3^6)(x^{12})][y^{-3}zx^8]$
$(3^6)(x^{12})(y^{-3})(z)(x^8)$
$(3^6)(x^{12})(x^8)(y^{-3})(z)$
$(3^6)(x^{20})(\frac{1}{y^3})(z)$
$\frac{3^6x^{20}z}{y^3}$
$\frac{729x^{20}z}{y^3}$

3 0

3 years ago

Can anyone please help me with this?

madam [21]

Using difference of squares

$a^{2} -b^{2}$ =(a-b)(a+b)

with a = x and b = 3 $\sqrt{2}$ i

$x^{2}$ + 18 =(x-3 $\sqrt{2}$ i)(x+3 $\sqrt{2}$ i)

4 0

3 years ago