There is a problem with your question. it doesn't make sense ???
Answer with Step-by-step explanation:
Suppose that a matrix has two inverses B and C
It is given that AB=I and AC=I
We have to prove that Inverse of matrix is unique
It means B=C
We know that
B=BI where I is identity matrix of any order in which number of rows is equal to number of columns of matrix B.
B=B(AC)
B=(BA)C
Using associative property of matrix
A (BC)=(AB)C
B=IC
Using BA=I
We know that C=IC
Therefore, B=C
Hence, Matrix A has unique inverse .
Answer:
X^2-18x+81
OR
(X-9)^2
Step-by-step explanation:
X(x-9)-9(x-9)=
x^2-9x-9x+81
X^2-18x+81
Answer:
x=−4 /3
Step-by-step explanation:
Answer:
I believe it is B
Step-by-step explanation:
