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Angelina_Jolie [31]
2 years ago
7

I just need help it seems easy but not for me

Mathematics
2 answers:
damaskus [11]2 years ago
4 0

Answer:

7 paperbacks, 2 hardcovers

Step-by-step explanation:

2x8=16

7x5=35

35+16=51

Hope this answers your question.

Nezavi [6.7K]2 years ago
3 0
Two hand covers and seven paperbacks
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8 6/7 =<br><br> i want it in fraction form and in the smallest form.
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Enrique is going to a party this weekend. He is bringing 20 liters of soda to the party. A liter of soda costs $1.59.
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3 years ago
12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5
Gnesinka [82]

\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

  • RS || PQ,

  • RS = 3 cm,

  • PQ = 6 cm,

  • ar(∆ TRS) = 15 sq. cm

As it is given that, <u>RS || PQ</u>

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

3 0
2 years ago
Someone please help me with this.
svetlana [45]

Answer:

9

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m = j^2 -7p

18 = j^2 -7(9)

18 = j^2 - 63

81 = j^2

√81 = √j^2

9 = j

6 0
3 years ago
Read 2 more answers
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