Answer:
int i = 0; i < names.size(); i++
Explanation:
The ArrayList must be read in the forward direction, and it is going to start from 0 certainly. Also, the iteration is going to end when i is exactly one less than the size of the ArrayList. And this is possible only if we choose the option mentioned in the Answer section. In this, i starts from 0 and iterates till i is one less than name.size() which is the size of the ArrayList.
put a thumb tack on his/her chair so he/she will sit on it!
As an Junior IT technician in your company. One of the responsibilities is to set up and Install computer structures for the new intern staff members in order to display and explain how the computer functions to them.
How will you address one or more technical areas?
Depending on the dimensions of the employer you account for, the answer varies. It's not uncommon for a technical IT support team to be split into first- and second-line support, with the second-line support team taking care of the more specialist inquiries that the first-line support team couldn't handle.
I'll explain how to set up and configure computer systems, identify hardware and software issues, and resolve technical and awareness issues, either over the phone or in person, in my capacity as an IT technician.
Learn more about organisations here:
brainly.com/question/26965722
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Answer:
Replace the comment
//Write your code here
with
for(int i =5; i<=500;i++){
System.out.print(i+" ");
if(i%50 == 0){
System.out.println();
}
}
Explanation:
See attached for the full program
This line iterates from 5 to 500
for(int i =5; i<=500;i++){
This prints each digit
System.out.print(i+" ");
<em>The following if condition checks if current digit is a multiple of 5; if yes, a line is printed</em>
<em>if(i%50 == 0){</em>
<em>System.out.println();</em>
<em>}</em>
}