Answer:
The internet allows you to connect with people and information around the world. The internet is more broad and could include searching things up or message-based websites. Emails is more specific, with it being when you send someone a message (called an email) on a mail website (that allows you to get messages from other people, websites, etc.)
Explanation:
In my answer.
The code that carried out the functions indicated above is stated below. It is not be noted that the code is written in C#
<h3>
What is C#</h3>
C# is a type-safe, object-oriented programming language. It is pronounced "see sharp"
<h3>
What is the code for the above task?</h3>
Using System;
public class HoursAndMinutes
{
public static void Main()
{
// declaring minutes variable and assigning 197 as given in question
int minutes = 197;
// outputing the total minutes , hours
Console.WriteLine("{0} minutes is {1} hours and {2} minutes.", minutes, minutes/60, minutes%60);
}
}
// OUT
Learn more about C#:
brainly.com/question/20211782
#SPJ1
Answer: (D) Distributed denial- of- service (DDoS)
Explanation:
The distributed denial of service attack is one of the type of attack that occur when the multiple system are basically flooded with the resources and the bandwidth.
- Botnet is one of the example of DDoS as it caused the DOS (denial of service) for the users.
- This type of attack is more substantial as compared to the DoS attack as they use the multiple system for attack the single target simultaneously.
Therefore, Option (D) is correct.
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
