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Andrews [41]
3 years ago
11

What is the directrix of y=1/8x^2. A. X=-2 B. Y=-2 C. Y= 2

Mathematics
1 answer:
castortr0y [4]3 years ago
8 0
B verified through apex
You might be interested in
Question 3
Ymorist [56]

To write an equation to represent a given information, the equations are to

expresses the information conveyed in the situation.

The two equations that represent the given information are;

  • <u>x + y = 25</u>
  • <u>5.6·x + 4·y = 133.6</u>

Reasons:

The given information are;

Mass of the large boxes = 5.6 kg

Mass of the small boxes = 4 kg

Number of boxes delivered = 25 boxes

Total mass of the boxes delivered = 133.6 kg

Number of the 5.6 kg box delivered = x

Number of the 4 kg boxes delivered = y

Required:

To form two equations in terms of <em>x</em> and <em>y</em> to represent the situation.

Solution:

The two equations are;

  • The number of boxes delivered = <u>x + y </u><u>= 25</u>
  • Total weight of the boxes delivered = <u>5.6·x + 4·y </u><u>= 133.6</u>

<em>Solving the above equations with a graphing calculator gives;</em>

  • <em>x = 21, y = 4</em>

<em />

Learn more about writing equations here:

brainly.com/question/15790322

5 0
2 years ago
Need help !!!!!!!!!!!!!!!!!!!!!!!
stich3 [128]
Answer:  " m∠SRW = 95 ° " .
________________________________________________

Since m∠TRV = 95° ; 

and:  ∠TRV and ∠SRW are vertical angles; 

and:  we are given:  " m∠TRV = 95° " ; 

and:  vertical angles are congruent; 

So, m∠TRV = m∠SRW = 95°  .
_______________________________________________
4 0
3 years ago
This one is for question #7
Varvara68 [4.7K]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can someone help me solve this please
natali 33 [55]
67 percent is your answer

7 0
4 years ago
The lifetimes of a certain type of light bulbs follow a normal distribution. If approximately 2.5% of the bulbs have lives excee
spin [16.1K]

Answer:

Mean = 339 hours

Standard deviation = 54 hours

Step-by-step explanation:

We are given that approximately 2.5% of the bulbs have lives exceeding 445 hours

So,P(x>445) = 0.025

P(x<445) =1- 0.025 =0.975

 z value for 0.975 is 1.96

Formula : z=\frac{x-\mu}{\sigma}

So, 1.96=\frac{445-\mu}{\sigma}

1.96 \sigma =445-\mu--A

Now we are given that  approximately 16% have lives exceeding 393 hours,

So,P(x>393) = 0.16

P(x<393) =1- 0.16 =0.84

 z value for 0.84 is 1

Formula : z=\frac{x-\mu}{\sigma}

So, 1=\frac{393-\mu}{\sigma}

1 \sigma =393-\mu ---B

Solve A and B

Substitute the value of \sigmafrom B in A

1.96 (393 -\mu) =445-\mu

770.28 -1.96\mu=445-\mu

770.28 -445=1.96\mu-\mu

325.28=0.96\mu

\frac{325.28}{0.96}=\mu

338.83=\mu

Substitute the value in B

\sigma =393-338.83

\sigma =54.17

So, mean = 339 hours

Standard deviation = 54 hours

5 0
3 years ago
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