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Sindrei [870]
3 years ago
13

If Hanna extends the pattern in the highlighted rows to include a ratio that has a first term of 20, what would be the second te

rm of the ratio ?
Mathematics
1 answer:
podryga [215]3 years ago
5 0

Answer:

why do i see these so late

Step-by-step explanation:

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Name each polygon. Determine if it appears to be regular or not regular, pentagon
steposvetlana [31]

Answer:

where are the polygons

4 0
3 years ago
The sum of two numbers is 104. The larger number is 3 more than the smaller number.
alexdok [17]
50.5 and 53.5
104-3=101 divided by 2=50.5 50.5+3 equals 53.5. 50.5+53.5=104
5 0
3 years ago
Can someone help me please
rusak2 [61]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The sum is formed by adding corresponding elements. For example, the lower right element (row 3, col 3) of the sum is 5+4 = 9

3 0
3 years ago
Find the vertex of the function given below. y = x2 - 4x + 1
DedPeter [7]
The vertex is (2, -3).
Use the formula x= -b/2a to find the x value., which is 2.Then, substitute it into the function, wherever you see an x. Follow order operations and you get y, which is -3.
5 0
3 years ago
Read 2 more answers
How do you get x trigonometry
Svetlanka [38]
Quick vocab:
sin=sine
cos=cosine
tan=tangent
theta=the angle
o=opposite side from angle
h=hypotenuse of triangle
a=adjacent side to angle

Three equations:
sin(theta)= o / h
cos(theta)= a / h
tan(theta)= o / a

Explanation of problem:

sin(x)= o / h
sin(x)= 16cm / 28cm
You'll substitute the 16cm in for o and 28cm for h
This is because 16cm is on the side that's opposite from the angle
28cm is on the hypotenuse of the triangle
One way to find the hypotenuse is look where the 90° is at and it's opposite from that

since you're trying to find the angle you'll have to inverse the sin to get it on the other side of the equal sign
Inverse is doing the opposite of so the inverse of sin is sin^-1

{ \sin}^{ - 1} (\frac{16cm}{28cm})
x = sin^-1 (16cm/28cm)

Answer:

x = 34.84990458°

I don't know how far rounded you'll need it
I hope this helped!
7 0
3 years ago
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