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3 years ago

13

If Hanna extends the pattern in the highlighted rows to include a ratio that has a first term of 20, what would be the second te

rm of the ratio ?

1 answer:

podryga [215]3 years ago

5 0

Answer:

why do i see these so late

Step-by-step explanation:

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Please helppppp meeeeeee!!!!!!!!!!!!!!!!!!!!

astraxan [27]

Answer:option A is the correct answer.

Step-by-step explanation:

The given triangle UVW is a right angle triangle. This is because one of its angles is 90 degrees. The sum of the two other angles is 180. To determine Cos U, we will apply trigonometric ratio.

Cos U = adjacent side/ hypotenuse.

Looking at the triangle with C as the reference angle,

Adjacent side = 12

Hypotenuse( always the longest side of the triangle) = 13

Therefore,

Cos U = 12/13

6 0

3 years ago

A bag contains a mixture of identical coloured balls.

Amiraneli [1.4K]

Answer:

72 yellow balls

Step-by-step explanation:

80% of 90 is (0.80*90) = 72 yellow balls.

5 0

2 years ago

I need help, sleps plzz , i dont understand plzzz dont ignoree!!!!!!!!!!!!

denpristay [2]

Answer:

x = $\frac{3+\sqrt{105} }{8} , \frac{3-\sqrt{105} }{8} x=1.655,-0.905$

Step-by-step explanation:

3x+6 = 4x^2

4x^2 -3x -6 = 0

x = $\frac{3+\sqrt{105} }{8} , \frac{3-\sqrt{105} }{8} x=1.655,-0.905$

7 0

3 years ago

In the same year, the average finishing time for u.s. women was four hours and 41 minutes. What was their average speed in miles

EleoNora [17]

I need to know the distance.

speed= distance/ time

If you want to figure thier speed you need to divide the distance ( miles) by their time ( hours)

3 0

3 years ago

Read 2 more answers

WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"

Feliz [49]

Recall Euler's theorem: if $\gcd(a,n) = 1$ , then

$a^{\phi(n)} \equiv 1 \pmod n$

where $\phi$ is Euler's totient function.

We have $\gcd(9,32) = 1$ - in fact, $\gcd(9,32^k)=1$ for any $k\in\Bbb N$ since $9=3^2$ and $32=2^5$ share no common divisors - as well as $\phi(9) = 6$ .

Now,

$37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} = 32\cdot\left(32^{(\cdots)}\right)^6$

where the $c_i$ are positive integer coefficients from the binomial expansion. By Euler's theorem,

$\left(32^{(\cdots)\right)^6 \equiv 1 \pmod9$

so that

$32^{37^{32}} \equiv 32\cdot1 \equiv \boxed{5} \pmod9$

7 0

1 year ago