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madam [21]
3 years ago
9

Mr smith earn 1900 each week and his wife earns 1150 each week they need to set aside 300 for food 90 for gas 875 for the mortga

ge and 400 for savings how much money will they have left each week
Mathematics
1 answer:
QveST [7]3 years ago
4 0

answer

1385

explanation

to find the total, subtract the amount they earned by the amount they spend

total = earned - spent

earned

each week, Mr. Smith earns 1900 and and his earns 1150, so add these values together to find the total amount they earn

earned = 1900 + 1150

earned = 3050

spent

they spend money on food, gas, mortgage, and savings, so add these values together to find the total amount they spend

spent = food + gas + mortgage + savings

spent  = 300 + 90 + 875 + 400

spent = 1665

total

now that we know how much they earn and spend, we can find the total

total = earned - spent

total = 3050 - 1665

total = 1385

every week they have 1385 left over

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Let the numbers be 5x and 7x
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A square has a perimeter of 24x² +16. What is<br> the length of each side of the square
hammer [34]

Answer:

6x² + 4

Step-by-step explanation:

The 4 sides of a square are equal in measure.

Divide the perimeter by 4 for length of side, that is

side = \frac{24x^2+16}{4} = \frac{24x^2}{4} + \frac{16}{4} = 6x² + 4

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3 years ago
Test the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test. Upper H 0H0​: pequals=0.40.4 ve
r-ruslan [8.4K]

Answer:

z=\frac{0.44 -0.4}{\sqrt{\frac{0.4(1-0.4)}{125}}}=0.913  

p_v =P(z>0.913)=0.181  

So the p value obtained was a very high value and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the population proportion is not higher than 0.4.  

Step-by-step explanation:

Data given and notation

n=125 represent the random sample taken

\hat p=\frac{55}{125}=0.44 estimated proportion

p_o=0.4 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is greater than 0.4:  

Null hypothesis:p\leq 0.4  

Alternative hypothesis:p >0.4  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.44 -0.4}{\sqrt{\frac{0.4(1-0.4)}{125}}}=0.913  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =P(z>0.913)=0.181  

So the p value obtained was a very high value and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the population proportion is not higher than 0.4.  

8 0
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Help please me please :') math bad for meh
tino4ka555 [31]

Answer:

first one : XAW = 50

second : z = 154

Step-by-step explanation:

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1:3 is equivalent to this
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