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Keith_Richards [23]
2 years ago
9

A gym charges $8.75 for each swimming class and a one-time registration fee of $12.50. A student paid a total of $56.25. How man

y swim classes did the student take?
Mathematics
1 answer:
cestrela7 [59]2 years ago
7 0

Answer:

He took 5 swimming classes.

Step-by-step explanation:

The problem states that the student paid a total of $56.25 for the classes and also the one-time registration fee. To find the number of classes, we should first subtract the one-time registration fee from the total.

$56.25 - $12.50 = $43.75

Now that we know he spent a total of $43.75 on the classes without the registration fee, we can divide that number by the cost of one class ($8.75) to calculate the total number of classes he took.

43.75 / 8.75 = 5

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Answer:

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What is the area of the trapezoid to the nearest tenth? <br> PICTURE BELOW ⬇⬇⬇⬇
Nastasia [14]

Answer:

  62.4 ft²

Step-by-step explanation:

The unmarked horizontal dimension at the bottom of the triangle is ...

  (8 ft)sin(30°) = 4 ft

The unmarked vertical dimension of the triangle (the height of the trapezoid) is ...

  (8 ft)cos(30°) ≈ 6.93 ft

Then the area of the trapezoid is given by the formula ...

  A = (1/2)(b1 +b2)h

  A = (1/2)((4 ft+7 ft) +(7 ft))(6.93 ft) ≈ 62.4 ft²

_____

The mnemonic SOH CAH TOA can remind you of the relationships between right triangle dimensions and angles.

  Sin = Opposite/Hypotenuse   ⇒   Hypotenuse×Sin = Opposite

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3 years ago
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Answer:

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2 years ago
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. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?
UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

<u>As we know:</u>

<u />Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \  of\ I-pad}

5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2

a) Thus, the total width of the I-Pads are 61.2 inches.

Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \  of\ Kindles}

4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4

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Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles \div Combined number of observations

Combined mean of width of the 12 I-Pads and 8 Kindles = \frac{99.6}{20} =4.98\ inches

c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.

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Thus, 7 units to the left of -1 is -8.

The appropriate choice is ...

... c. -8

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2 years ago
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