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vekshin1
2 years ago
8

Please answer!! I tried doing it myself and it didn’t work. Again pls answer! Rewards are 20 points

Mathematics
2 answers:
Damm [24]2 years ago
4 0

Answer:-45

Step-by-step explanation:this is how I do it: draw a line in the middle of the equal sign. Now its split in two parts. Do the opposite operation on the left side, so minus 6 from the left AND the right. Now it equals to y/3 = -15. Now times each side by 3 so the y stands alone. -15 times 3 equals -45. Y = -45. Sorry it's kinda hard to explain!

N76 [4]2 years ago
4 0

Answer:

y =  - 45

Step-by-step explanation:

\frac{y}{3}  + 6 =  - 9

\frac{y}{3}  + 6 \:  - 6 =  - 9 - 6

3 \times \frac{y}{3}  =  - 15 \times 3

y =  - 15 \times 3

y =  - 45

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Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca
Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

\frac{dQ}{dt} = -rt

Which has the following solution:

Q(t) = Q(0)e^{-rt}

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that Q(6) = (1-0.03)Q(0) = 0.97Q(0). We use this to find r.

Q(t) = Q(0)e^{-rt}

0.97Q(0) = Q(0)e^{-6r}

e^{-6r} = 0.97

\ln{e^{-6r}} = \ln{0.97}

-6r = \ln{0.97}

r = -\frac{\ln{0.97}}{6}

r = 0.0051

So

Q(t) = Q(0)e^{-0.0051t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.0051t}

0.5Q(0) = Q(0)e^{-0.0051t}

e^{-0.0051t} = 0.5

\ln{e^{-0.0051t}} = \ln{0.5}

-0.0051t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.0051}

t = 135.9

The half-life of the radioactive substance is 135.9 hours.

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2 years ago
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Answer:

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