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3 years ago

I nEeD hElP!!!!!!!! I WILL GIVE 20 PONITSSSS

Mathematics

2 answers:

dexar [7]3 years ago

6 0

Answer:

True

Step-by-step explanation:

This is because when you look at the graph you see that when you line it up, it lines up with each other

vlada-n [284]3 years ago

4 0

Answer:

True if im not mistaken

Step-by-step explanation:

You might be interested in

Use the function f(x) to answer the questions.

fiasKO [112]

Answer:

Below in bold.

Step-by-step explanation:

A. −16x2 + 24x + 16 = 0

-8(2x2 - 3x - 2) = 0

-8(2x + 1 )(x - 2) = 0

x = -0.5, 2.

So the x-intercepts are (-0/5, 0) and (2, 0).

B. As the leading coefficients is negative (-16) the vertex of the graph will be a Maximum.

To find its coordinates we convert the function to vertex form:

f(x) = −16x2 + 24x + 16

= -16(x^2 - 1.5x) + 16

Completing the square on contents of the parentheses:

= -16 [(x - 0.75)^2 - 0.75^2] + 16

= -16(x - 0.75)^2 - 16 * -0.75^2 + 16

= -16(x - 0.75)^2 + 9 + 16

= -16(x - 0.75)^2 + 25.

So the coordinates of the vertex are (0.75, 25)

3 0

2 years ago

You work in the HR department at a large franchise. you want to test whether you have set your employee monthly allowances corre

ra1l [238]

Answer:

1) Null hypothesis: $\mu \leq 500$

Alternative hypothesis: $\mu > 500$

$z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90$

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

$z_{crit}= 2.33$

For this case we see that the calculated value is higher than the critical value

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

2) Since is a right tailed test the p value would be:

$p_v =P(z>5.90)=1.82x10^{-9}$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

Step-by-step explanation:

Part 1

Data given

$\bar X=640$ represent the sample mean

$\sigma=150$ represent the population standard deviation

$n=40$ sample size

$\mu_o =500$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Step1:State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is higher than 500, the system of hypothesis would be:

Null hypothesis: $\mu \leq 500$

Alternative hypothesis: $\mu > 500$

Step 2: Calculate the statistic

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

We can replace in formula (1) the info given like this:

$z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90$

Step 3: Calculate the critical value

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

$z_{crit}= 2.33$

Step 4: Compare the statistic with the critical value

For this case we see that the calculated value is higher than the critical value

Step 5: Decision

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

Part 2

P-value

Since is a right tailed test the p value would be:

$p_v =P(z>5.90)=1.82x10^{-9}$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

7 0

3 years ago

Nine less than the product of a number n and 1/6 is no more than 92

SSSSS [86.1K]

Answer:

Please help im on that 2dd

Step-by-step explanation:

dddd

7 0

2 years ago

the length of a rectangle is 8in. more than it’s width. the perimeter of the rectangle is 88in. what are the width and length of

bixtya [17]