Answer: Pentanol and propanoic acid
Explanation:
Alkanoates ( esters ) are condensation products of the reversible reaction between an alkanol and an alkanoic acid in the presence of a mineral acid which acts as a catalyst.
Alkanol + Alkanoic acid = Alkanoate(ester) + water
ROH + RCOOH = RCOOR + H2O
E.g
Ethanol + Ethanoic acid = Ethylethanoate + water
C2H5OH + CH3COOH = CH3COOC2H5 + H2O
The forward reaction is called esterification while the reverse reaction is called acid hydrolysis.
In naming esters, the end alkyl, R, from the alkanol is named first as alkyl before the RCOO- is then named by replacing the -oic acid with -oate.
E.g CH3COOCH3 is methylethanoate.
C2H5COOCH3 is methylpropanoate.
Esters undergo acid hydrolysis (the acid acts as the catalyst) in the presence of water to yield the alkanols and alkanoic acids that formed them.
E.g
ethylethanoate + water = ethanol + ethanoic acid.
Note that the ethanol is from the ethyl and ethanoic acid from the ethanoate.
For the above question:
Pentylpropanoate + water = pentanol + propanoic acid
C2H5COOC5H11 + H2O = C5H11OH + C2H5COOH