Based on the scenario, that is not needed to calculate the mass of the calcium oxide is : D. the volume of the unknown mass
In order to find out the mass of a product, you just need the mass of the reactants and the mass of the product
hope this helps
Dissociation of Pb₃(PO₄)₂ is;
Pb₃(PO₄)₂(s) ⇆ 3Pb²⁺(aq) + 2PO₄³⁻(aq)
initial - -
change -X +3X +2X
Equilibrium 3X 2X
Ksp = [Pb²⁺(aq)]³ [PO₄³⁻(aq)]²
1.0 x 10⁻⁵⁴ = (3X)³ (2X)²
1.0 x 10⁻⁵⁴ = 108X⁵
X = 6.21 x 10⁻¹² M
Hence the molar solubility of Pb₃(PO₄)₂ is 6.21 x 10⁻¹² M.
