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victus00 [196]
2 years ago
8

The central limit theorem states that sampling distributions are always the same shape as the population distribution from whenc

e the data came. True or False
Mathematics
1 answer:
sergejj [24]2 years ago
3 0

Explanation:

The sample mean is not always equal to the population mean but if we take more and more number of samples from the population then the mean of the sample would become equal to the population mean.

The Central Limit Theorem states that we can have a normal distribution of sample means even if the original population doesn't follow normal distribution, But we have to take a lot of samples.

Suppose a population doesn't follow normal distribution and is very skewed then we can still have sampling distribution that is completely normal if we take a lot of samples.

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adoni [48]

Answer:

She is at least 51. She could be older.

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The answer for the first blank would be 1/2 because it had been dilated down to half it's original size. I hope this helps!
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3 years ago
What are the zeros of the function defined by the polynomial<br> x2 + 7x+12?
ryzh [129]

Answer:

x = -4 and -3

Step-by-step explanation:

factors to (x+4)(x+3)

to zero them is -4 and -3

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4 0
2 years ago
Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ &lt; 55 A sample of 36 is used. Identify the p-value and state your con
Ket [755]

Answer:

Step-by-step explanation:

Given that:

H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }

Z = \dfrac{-1}{\dfrac{5.3}{6} }

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

b

For x = 53 and s = 4.6

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }

Z = \dfrac{-2}{\dfrac{4.6}{6} }

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

Conclusion: \  There  \ is \  sufficient \  evidence  \  to \  conclude \  that \mu < 55

c)

For x = 56 and s = 5.0

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

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3 years ago
suppose that O has coordinates (0,0),and the points P and Q have coordinates that are whole numbers between 0 and 2, inclusive.
pishuonlain [190]

Answer:

Step-by-step explanation:

suppose that O has coordinates (0,0),and the points P and Q have coordinates that are whole numbers between 0 and 2, inclusive. One example of a triangle with O,P, and Q as vertices is shown below . how many such triangle are right triangle ?

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