This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
</u><u /><u />
If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
Answer:
A
<em>brainliest is much appreciated!</em>
Step-by-step explanation:
hope this helps!
Answer:
options 2,4 and 6 should be correct.
Step-by-step explanation:
You forgot the image , here if you want some free points to repost it just go to a point put a bogus answer in one of my questions . That mistake happens to me all the time