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tester [92]
3 years ago
11

The graph shows a proportional relationship between x and y.Find the constant of proportionality (r) and write an equation to re

present the relationship.

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
6 0

Answer:

r=3

y=3x

Step-by-step explanation:

We are given that a graph.

The graph shows  a proportional relationship between x and y.

From given graph  we can see that when x increases then y is also increases.

Therefore, y\propto x

y=rx

Where r=proportionality constant

x=5 and y=15

Substitute the values then we get

15=r(5)

r=\frac{15}{5}=3

Substitute the value of r

Then, the equation to represent the relationship is given by

y=3x

damaskus [11]3 years ago
5 0
The constant of proportionality (r) appears to be 3.

y = 3x . . . . . . . x = number of tickets sold; y = dollars collected
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A particular shoe store stocks two styles of walking shoes. Style A sells for $66.95 and Style B sells for $84.95. At the end of
Gnom [1K]

Answer:

Style A shoes sold : <u>152</u>

Style B shoes sold : <u>88</u>

Step-by-step explanation:

Let :

  • Style A shoes = x
  • Style B shoes = y

Forming equations :

  1. x = 2y - 24
  2. 66.95x + 84.95y = 17,652

Substitute the value of x from 1 in 2.

  • 66.95 (2y - 24) + 84.95y = 17,652
  • 133.90y - 1606.80 + 84.95y = 17,652
  • 218.85y = 19258.80
  • <u>y = 88</u>

<u />

Finding x :

  • x = 2(88) - 24
  • x = 176 - 24
  • <u>x = 152</u>

<u />

Solution :

  • Style A shoes sold : <u>152</u>
  • Style B shoes sold : <u>88</u>
8 0
2 years ago
Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8​
Ivanshal [37]

It looks like the differential equation is

\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}

Factorize the right side by grouping.

xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)

xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)

Now we can separate variables as

\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx

Integrate both sides.

\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx

\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx

\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}

You could go on to solve for y explicitly as a function of x, but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

8 0
2 years ago
HELP ASAP WILL GIVE BRAINLIEST
Alona [7]

Answer:

y=2x^{2} -7x-4

three linear equations

c=-4 ;4a+b=1 ; 9=a-b

Step-by-step explanation:

Simply assume a standard parabola equation y=ax^{2} +bx +c

(here a, b, c are three independent variables)

Three coordinates as shown in graph are (0,4), (4,0) ,(-1,5)

Now put these points in the equation of parabola and get three linear equations.

[1] c=-4

[2] 4a+b=1

[3] 9=a-b

 Now substitute value of a from equation 2 into 3 in terms of b

 a=  \frac{1-b}{4}

 9=\frac{1-b}{4}-b

 b=-7

 a=2

y=2x^{2} -7x-4

6 0
3 years ago
Which of the following sentences could not be used to represent the equation x-5 = -10?
e-lub [12.9K]
A number subtracted from five is equal to negative ten
3 0
3 years ago
Read 2 more answers
What’s the value for y?
galina1969 [7]
Y=3(2)-2
Y=6-2
Y=4
The value of y is 4.
6 0
3 years ago
Read 2 more answers
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