Answer:
i need a pic
Step-by-step explanation:
The area will be equal to Area = (28)(21) / 2 = 294 square inches.
<h3>What is the area?</h3>
To determine the area of a triangle, we calculate one half of the product of the base and the height of the triangle so we need data on its base and its height. We are given the following:
Hypotenuse = 7 + base = 14 + height
Perimeter = 84 inches
The perimeter of the triangle is equal to the sum of the three sides of the triangle which are the height, base and hypotenuse. So,
Perimeter = height + base + hypotenuse = 84
We let x = height and y = base. We calculate area as follows:
84 = x + y + (7 + y)
77 = x + 2y
x = 77 -2y
The Hypotenuse is related to the other sides by the Pythagorean theorem.
Hypotenuse^2 = (x^2 + y^2)
(14 + x)^2 = x^2 + y^2
(14 + (77-2y))^2 = (77-2y)^2 + y^2
(91-2y)^2 = (77-2y)^2 + y^2
Solving for y and x
y = 28
x = 21
Area = (28)(21) / 2 = 294 square inches
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Answer:
a. 215.6 in^3
b. 1.51 lb
Step-by-step explanation:
The area of each hand grip hole is that of a circle of radius 0.6 in together with a rectangle 2 in long and 1.2 in wide. So, that area is ...
π·(0.6 in)^2 + (2 in)(1.2 in) = (0.36π +2.4) in^2
The area of the kickboard before the hand grip holes are put in is that of a semicircle of radius 5.5 in together with a rectangle 12 in long and 11 in wide. So, that area is ...
(1/2)·π·(5.5 in)^2 + (12 in)(11 in) = (15.125π +132) in^2
Taking the hand grip holes out, the top area of the board is ...
((15.125π +132) -2(0.36π +2.4)) in^2
= (14.405π + 127.2) in^2
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a. The volume is the product of the area and the thickness, so is ...
((14.405π +127.2) in^2)·(1.25 in) ≈ 215.568 in^3
__
b. The weight of the kickboard is the product of its volume and its density:
(215.568 in^3)(0.007 lb/in^3) ≈ 1.509 lb
