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Mamont248 [21]
3 years ago
13

what is the units digit of the sum of 1!+2!+3! ... n! when n=2019. Include an explanation and what a unit digit is.

Mathematics
1 answer:
horsena [70]3 years ago
8 0

Hey!

Finding the factorial for the first few numbers, we have:

1!=1

2!=2

3!=6

4!=24

5!=120

6!=720

7!=720*7

8!=720*56

What we can see as a clear pattern from 5! and on is that our number ends with a 0, making the units digit 0. Therefore, when we add the units digit of 5! and on, we have a result of 0. So, we can simply add the units digits of 1!, 2!, 3!, and 4!, which is 1+2+6+4=13. Since the units digit is the last number, we can drop the tens place to get an answer of 3.


Feel free to ask further questions!

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(-∞, -2) ∪ (0, ∞)

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Multiply together the (7x) and the (x+2), obtaining 7x^2 + 14x.  This is the correct argument (input) to Answer A.

Since the domain of the square root function includes "all real numbers equal to or greater than 0," we set 7x^2 + 14x = to 0.  This factors to the original 7x*(x+2), set equal to 0.  The roots are 0 and -2.  

These two values create three intervals:  (-∞, -2), (-2, 0) and (0, ∞).

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7x^2 + 14x is + at x = -5, - at x = -1, and + at x = 1.

Thus, the domain of this function is  (-∞, -2) ∪ (0, ∞).  In other words, the product shown is defined on  (-∞, -2) ∪ (0, ∞).

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This problem can be written as:

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Let \mu = <u><em>population mean amount packaged. </em></u>

So, Null Hypothesis, H_0 : \mu = 8.17 ounces    {means that the mean amount packaged is equal to 8.17 ounces}

Alternate Hypothesis, H_A : \mu\neq 8.17 ounces    {means that the mean amount packaged is different from 8.17 ounces}

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