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Amiraneli [1.4K]
3 years ago
6

What is 1.825 rounded to the nearest hundredth

Mathematics
2 answers:
Black_prince [1.1K]3 years ago
4 0
 it's 1.83   no problem ;)
vovangra [49]3 years ago
3 0
The answer is 1,800 because if you free your number line that is the answer you will get see

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The perimeter of a rectangular swimming pool is 446 centimeters. The width of the pool is 7 centimeters less than the length of
VLD [36.1K]

Answer:

length = 115 cm

width = 108 cm

Step-by-step explanation:

The perimeter of a rectangular swimming pool is 446 centimeters

LEt L be the length of the pool

The width of the pool is 7 centimeters less than the length of the pool.

width = length - 7

W= L-7

Given perimeter = 446

Perimeter of rectangle = 2(length)+2(width)

446 = 2(L) + 2(W)                    we know W = L-7

446 = 2(L) + 2(L-7)    

446 = 2L + 2L - 14

Add 14 on both sides

460 = 4L

divide by 4 on both sides

L= 115

Length L= 115

Width W = L - 7 = 115 - 7= 108

5 0
3 years ago
Read 2 more answers
Work out the circumference of this circle.
tigry1 [53]
C=pid
Since d=9m and pi=3.142, C=3.142*9m=28.278
Rounded to 1 decimal point =28.3
3 0
3 years ago
Factor each expression<br>(9 &amp; 10)
s344n2d4d5 [400]
9)
8x+4*6
8x+24

11) 
3t+2c=6tc
7 0
3 years ago
Pls help see (pic posted)
PolarNik [594]

Answer:

<h2>AB=8.4 inches</h2><h2>AC=13.05 inches</h2>

Solution,

\frac{ab}{bc}   = tan \: 40 \\ ab = bc \times tan \: 40 \\ ab = 10 \times 0.84 \\ ab = 8.4 \: inches \:

\frac{bc}{ac}  = cos \: 40 \\  \frac{bc}{cos \: 40}   = ac \\ ac =  \frac{10}{cos \: 40}  \\ ac = 13.05 \: inches

Hope this helps...

Good luck on your assignment..

7 0
4 years ago
.......................
hodyreva [135]

Answer:

1) when tomato patch is 6.5 feet the area is 191.75 sq.ft

2)  when tomato patch is 7 feet the area is 217 sq.ft

3) when area is 338 sq.ft the tomato patch is 9.0778 feet

4) when area is 147.25 sq.ft the tomato patch is 5.543799 feet

Step-by-step explanation:

The given equation is  :

3x^2 + 10x

Length of Tomato (in feet)                                       x,  6.5   ,  x   ,     7

Patch Area of Vegetable Garden (in square feet) 338, x , 147.25, x

So we can find the missing terms with the help of the equation 3x^2 + 10x

Putting the values of x from the length of the tomato patch

1)  3x^2 + 10x= 3(6.5)²+ 10 (6.5)=126.75+ 65= 191.75 square feet

2) 3x^2 + 10x= 3(7)² +10 (7)= 147+70= 217 square feet

So the area of  her vegetable garden for a variety of  lengths of the tomato patch= 6.5 feet is 191.75  square feet

and for 7 feet is 217 square feet

Similarly we can find the length of the tomato patch from the area by again using the given equation  3x^2 + 10x

So when area = 338 square feet

The equation becomes  

3x^2 + 10x= 338

Rearranging it :     3x^2 + 10x-338 =0

This is a quadratic equation and can be solved with the help of the formula.

Here a= 3, b= 10 and c= -338

x = -b±√b²- 4ac/2a

Putting the values of a,b,c we get

x= -10±√100+ 4056/6

x= -10± 64.467/6

x= 54.467/6 or -74.467/6   we ignore the negative value because the garden cannot have the negative area.

x= 9.0778 feet

Similarly repeating the same process would give

So when area = 147.25 square feet

The equation becomes  

3x^2 + 10x= 147.25

Rearranging it :     3x^2 + 10x-147.25 =0

This is a quadratic equation and can be solved with the help of the formula.

Here a= 3, b= 10 and c= - 147.25

x = -b±√b²- 4ac/2a

Putting the values of a,b,c we get

x= -10±√100+ 1767/6

x= -10± 43.208/6

x= 33.208/6 or -53.208/6  we ignore the negative value because the garden cannot have the negative area.

x= 5.543799 feet

6 0
4 years ago
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