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3 years ago

How to solve -64 = -8(w+ 20)

1 answer:

5 0

W=-12

First you distribute the -8 using the distributive property.

So, -64= -8w-160

Next, you add 160 to both sides to put the same type of number (wand non-x) separate from each other.

The equation becomes 96=-8w

Then finally you divide -8 from both sides to get w by itself.

So 96/-8= -12.

w=-12.

Hope this helps!

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Please help me im doing a test

Reptile [31]

Answer:

D I think

Step-by-step explanation:

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3 years ago

I need help ASAP nowwwwwww plz 106=

polet [3.4K]

Answer:

r = 0.053 or 5.3%

Step-by-step explanation:

Formula:

I = Prt

Given:

I = 106

P = 10000

t = 73/365

Work:

I = Prt

r = I/(Pt)

r = 106/(10000 * 73/365)

r = 106/2000

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3 years ago

The cost of a t-shirt was $30. Now the t-shirt costs $37.50. What is the percent of change? Do the work on your own paper and wr

Art [367]

Answer:

25%

Step-by-step explanation:

Given that,

Initial cost of a t-shirt = $30

Final cost of a t-shirt = $37.50

We need to find percent of change. The percentage change in any value is given by :

$\%=\dfrac{\text{final value-initial value}}{\text{initial value}}\times 100\\\\=\dfrac{37.5-30}{30}\times 100\\\\=25\%$

Hence, the percentage error is 25%.

8 0

3 years ago

Help please!What is the x-intercept of the line?X=33 Y=-22X=52 Y=-33X=71 Y=-44

tekilochka [14]

x intercept is -5

Explanation

Step 1

find the slope of the line:

when you know 2 points of the line, you can find the slope, by using:

$\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}$

then,Let

P1(33,-22)

P2(52,-33)

replace,

$\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{-33-(-22)}{52-33}=\frac{-33+22}{19}=\frac{-11}{19} \\ \text{slope}=-\frac{11}{19} \end{gathered}$

Step 2

find the equation of the line

$y-y_1=slope(x-x_1)\rightarrow equation$

let

$\begin{gathered} \text{slope}=-\frac{11}{19} \\ P1(33,-22) \end{gathered}$

replace,

$\begin{gathered} y-y_1=slope(x-x_1)\rightarrow equation \\ y-(-22)=-\frac{11}{19}(x-33) \\ y+22=-\frac{11}{19}x+\frac{363}{19} \\ to\text{ isolate y, subtract 22 in both sides} \\ y+22-22=-\frac{11}{19}x+\frac{363}{19}-22 \\ y=-\frac{11}{19}x-\frac{55}{19}\rightarrow equation\text{ of the line} \end{gathered}$

now, we have the equation of the line, to get the x intercetp ( it is when y=0)

replace

$\begin{gathered} y=-\frac{11}{19}x-\frac{55}{19}\rightarrow equation\text{ of the line} \\ 0=-\frac{11}{19}x-\frac{55}{19} \\ \text{isolate x} \\ \frac{11}{19}x=-\frac{55}{19} \\ 11x=-\frac{55\cdot19}{19} \\ 11x=-55 \\ \text{divide both sides by 11} \\ \frac{11x}{11}=\frac{-55}{11} \\ x=-5 \end{gathered}$

so, the x intercetp is -5.

I hope this helps you