Answer:
m<−18
Step-by-step explanation:
Step 1: Simplify both sides of the inequality.
m+12<−6
Step 2: Subtract 12 from both sides.
m+12−12<−6−12
m<−18
You have to understand how piecewise functions first
I hope you do because I won't be explaining it here
1.
if it is continiuous at x=1 then the part of the function that approaches 1 from the left is the same value
so we have f(x)=3-x for x<1, so evaluate it for x=1,
we would get 3-1=2
so
if a=2 and b=3
f(x)=2x²+3x
for x=1, we get 2+3=5
it approaches 2 from the left but equals 5
2≠5
so it is not continuous because it doesn't approach the same value at x=1
2.
alright
so we established that it should approach 2 because we had the f(x)=3-x
so
f(1)=2=ax²+bx
2=a+b
the relationship is 2=a+b
3.
same as before, but use the other function, the one that is defined at x≥2
5x-10, 5(2)-10, 10-10, 0
it approaches 0
so
we must find one such that f(x)=0 for x=2 with the ax²+bx
0=a(2)²+b(2)
0=4a+2b
if we minus 2b both sides
-2b=4a
divide by 2
-b=2a
add b both sides
0=2a+b
4.
2=a+b
0=2a+b
2=a+b
minus b both sides
2-b=a
subsitute
0=2a+b
0=2(2-b)+b
0=4-2b+b
0=4-b
b=4
sub back
2-b=a
2-4=a
-2=a
a=-2
b=4
5.
graph f(x)=-2x²+4x from x=1 to x=2 and put a closed dot at (1,2) and an open dot at (2,0)
Answer:
the answer is a) term
Step-by-step explanation:
hope this helps! :)
brainliest?
Answer:
6/5 < x < 10/3 is the desired solution.
Step-by-step explanation:
Here, the given compound inequality is :
x + 1 < -2 x + 11 < 3 x + 5
Now, consider the first two term of the inequality, we get:
x + 1 < -2 x + 11
Subtracting 1 from both sides, we get:
x + 1 - 1 < -2 x + 11 - 1
or, x < -2x + 10
or, x + 2x < 10
or, 3 x < 10
or, x < 10/3
Similarly, considering the last two terms of the given inequality, we get:
-2 x + 11 < 3 x + 5
Subtracting 11 from both sides, we get:
-2 x + 11 - 11 < 3 x + 5 - 11
or, - 2 x < 3 x-6
or, 6 < 5 x
or, x > 6/5
Hence, combining two solutions, we get: 6/5 < x < 10/3
So, the desired value of x should be more than (6/5) but less than (10/3)
Answer:
Given
f(x) = 2x+7
g(x) = x^2-4
h(x) = 5x
a. 4h(x)
= 4 * 5x
= 20x
b. f(x) - g(x)
f(x) - g(x) = 2x + 7 - (x^2 - 4)
= 2x+7-x^2+4
=-x^2+2x+7+4
=-x^2+2x+11
c. f(g(x)) = 2(g(x))+7
=2(x^2-4) +7
=2x^2-8+7
=2x^2-1
d. g(x)h(x) = (x^2-4)(5x)
= 5x^3 - 20x
e. g(x) / f(x) = x2 - 4/ 2x + 7
