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Archy [21]
4 years ago
12

Tires from two different trucks are being compared. Tire A has a diameter of 32 inches and Tire B has a diameter of 28 inches. H

ow much farther dose Tire A travel compared to Tire B after one revolution? Round your wander to one decimal place. (remember to place the unit of measure [inches] after the numeral sender)
Mathematics
1 answer:
yuradex [85]4 years ago
7 0

Answer:

12.6 inches

Step-by-step explanation:

-The distance covered in one revolution is equivalent to the circumference oif a tire.

#We calculate the Circumference of A:

C_a=\pi D\\\\=\pi \times 32\\\\=100.5310\ inches

#We then calculate the circumference of B:

C_b=\pi D\\\\=\pi \times 28\\\\=87.9646\ inches

-A has a larger circumference than B and the difference is :

\bigtriangleup=C_a-C_b\\\\=100.5310-87.9646\\\\=12.5664\approx12.6\ inches

Hence, Tire A covers 12.6 inches more than B after one revolution.

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Which graph best represents y=3(x-3)^2+3​
jok3333 [9.3K]

Answer:

A line graph

which graph best represents y=3(x-3)^2+3​

Step-by-step explanation:

6 0
3 years ago
Use the net to find the surface area of the prism 8in 15in 17in 9in
exis [7]

Answer:

The surface area of the prism is <u>480 in²</u>.

Step-by-step explanation:

Given:

The prism dimensions are 8in 15in 17in and 9in.

Now, to find the surface area:

So, to get the surface area we put formula:

a=8in, b=15in, c=17in and h=9in.

Surface area = 2A+(a+b+c)h.

Whereas, A=\sqrt{s(s-a)(s-b)(s-c)}

And, s=\frac{a+b+c}{2}

<em>Now, we find </em><u><em>s</em></u><em> first:</em>

s=\frac{a+b+c}{2}

s=\frac{8+15+17}{2}

s=\frac{40}{2}=20.

<em>Then, we get</em><u><em> A </em></u><em>:</em>

A=\sqrt{s(s-a)(s-b)(s-c)}

A=\sqrt{20(20-8)(20-15)(20-17)}

A=\sqrt{20(12)(5)(3)}

<em>On solving we get:</em>

A=\sqrt{3600}=60.

Now, putting the value of A in the formula to get the surface area:

Surface area = 2A+(a+b+c)h.

Surface area = 2\times 60+(8+15+17)9.

Surface area = 120+(40)9.

Surface area = 120+360.

Surface area = 480\ in^2.

Therefore, the surface area of the prism is 480 in².

6 0
3 years ago
Compare the process of solving |x – 1| + 1 &lt; 15 to that of solving |x – 1| + 1 &gt; 15.
kicyunya [14]
In the first case we'd subtract 1 from both sides, obtaining |x-1|<14.

In the second case we'd also subtract 1 from both sides, and would obtain
 |x-1|>14.

What would the graphs look like?

In the first case, the graph would be on the x-axis with "center" at x=1.  From this center count 14 units to the right, and then place a circle around that location (which would be at x=15).  Next, count 14 units to the left of this center, and place a circle around that location (which would be -13).  Draw a line segment connecting the two circles.  Notice that all of the solutions are between -13 and +15, not including these endpoints.

In the second case, x has to be greater than 15 or less than -13.  Draw an arrow from x=1 to the left, and then draw a separate arrow from 15 to the right.  None of the values in between are solutions.

4 0
3 years ago
Read 2 more answers
What's the answer ?????
Sindrei [870]
20, I do believe. Quite Positive, though, might wanna check again
3 0
3 years ago
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The value of y varies directly with x. If x = 5 when y = 12, what is the value of x when y = 30?
sergiy2304 [10]

Answer:

12

Step-by-step explanation:

12/5 = 2.4

2.4(x)

if x = 5 then,

2.4(5) = 12

5 0
3 years ago
Read 2 more answers
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