I believe it would be any number that is within the darkest shaded area. (-4,1) seems like it would be correct.
Answer: 152
Step-by-step explanation: rep me if I’m wrong
Distributive Property because 12(x+4)= 12x (the first number or letter in the parenthesis times 12) plus 12x4 (the second number in the parenthesis)
So together it is:
12x+(12x4)
Answer:
Required center of mass 
Step-by-step explanation:
Given semcircles are,
whose radious are 1 and 4 respectively.
To find center of mass, 
, let density at any point is 
and distance from the origin is r be such that,
where k is a constant.
Mass of the lamina=m=
where A is the total region and D is curves.
then,
- Now, x-coordinate of center of mass is
. in polar coordinate 
![=3k\big[-\cos\theta\big]_{0}^{\pi}](https://tex.z-dn.net/?f=%3D3k%5Cbig%5B-%5Ccos%5Ctheta%5Cbig%5D_%7B0%7D%5E%7B%5Cpi%7D)
![=3k\big[-\cos\pi+\cos 0\big]](https://tex.z-dn.net/?f=%3D3k%5Cbig%5B-%5Ccos%5Cpi%2B%5Ccos%200%5Cbig%5D)
Then, 
- y-coordinate of center of mass is
. in polar coordinate 
![=3k\big[\sin\theta\big]_{0}^{\pi}](https://tex.z-dn.net/?f=%3D3k%5Cbig%5B%5Csin%5Ctheta%5Cbig%5D_%7B0%7D%5E%7B%5Cpi%7D)
![=3k\big[\sin\pi-\sin 0\big]](https://tex.z-dn.net/?f=%3D3k%5Cbig%5B%5Csin%5Cpi-%5Csin%200%5Cbig%5D)
Then, 
Hence center of mass
