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Nastasia [14]
2 years ago
10

If each side of a square grows 6 mm, the area of ​​the square is multiplied by 16. How long are the sides of the original square

?
Mathematics
1 answer:
Phoenix [80]2 years ago
3 0

Answer:

2 mm

Step-by-step explanation:

Let x be the sides of the original square,

then the area of the original square is x^2

The sides of the new square is x + 6

The area is (x + 6)^2

Then (x + 6)^2 = 16*x^2

Take square root on both sides and get

x + 6 = 4x,

3x = 6

so x = 2 mm

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abruzzese [7]

Complete Question

Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a² + b² = c², which in this isosceles triangle becomes a² + a² = c². By combining like terms, 2a² = c². Which final step will prove that the length of the hypotenuse, c, is StartRoot 2 EndRoot times the length of each leg?

a) substitute values for a and c into the original pythagorean theorem equation.

b) divide both sides of the equation by two, then determine the principal square root of both sides of the equation.

c) determine the principal square root of both sides of the equation.

d) divide both sides of the equation by 2.

Answer:

c) determine the principal square root of both sides of the equation.

Step-by-step explanation:

Pythagoras Theorem for a right angled triangles states that:

a²+ b²= c²

But for an Isosceles Triangle, where two sides of the triangle are equal, we have:

a²+ a² = c²

By combining like terms

2a² = c²

We square root both sides of the equation.

√2a² = √c

√2a² = c

The final step will prove that the length of the hypotenuse, c, is StartRoot 2 EndRoot times the length of each leg = √2a² = c is Option c.

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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This recipe makes 7 portions of chocolate mousse.
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3 years ago
A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

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8 0
3 years ago
If you explain and answer i will give brainly
CaHeK987 [17]

6x - 5y = 3          x1

3x - 8y = -15    x2

===============

6x - 5y = 3

6x - 16y = -30

============= -

11y = 33

y = 3

6x - 5(3) = 3

6x -15 = 3

6x = 18

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(3,3)

7 0
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