Answer:
81
Step-by-step explanation:
Move the decimal point to the right the number of places equal to the number of repeating digits. Subtract the original number. (Digits after the first instance of the pattern will be canceled.) Divide the result by a number of 9s equal to the number of repeating digits. Simplify the result.
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Example: 5.3181818_18
There are 2 repeating digits, so we subtract ...
... 531.8_18 -5.3_18 = 526.5
and divide by 99 . . . . . . two 9s, one for each of the two repeating digits
... = 526.5/99 = 5625/990 = 117/22 = 5 17/22
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More formally, if S is the value of the original number, and it has n repeating digits, you compute
.. (S·10^n - S)/(10^n -1) = S(10^n -1)/(10^n -1) = S
Most likely liters, but I'm not sure.
For number 7 since the rational number is countable, and the set of real numbers is uncountable, almost all real numbers are irrational. So you should choose false
8 yes! All whole numbers are integers. For an example 0 is a whole number, 0 Is ALSO a integer. So you should choose truth
(2^8 . 5^-5 . 19^0)^-2
using PEMDAS
this = (2^8 * 1/5^5 * 1)^-2
= (5^5 / 2^8)^2
= 5^10 / 2^16
mark me brainlest pls thxs