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3 years ago

Which binomials are a difference of squares?

Mathematics

1 answer:

kow [346]3 years ago

3 0

Answer:

Options B and C.

Step-by-step explanation:

Difference of squares is defined as

$a^2-b^2$

where, a and b both area real numbers.

$y^4+9\Rightarrow (y^2)^2+3^2$

It is sum of squares.

$9x^2-16\Rightarrow (3x)^2-4^2$

It is difference of squares.

$m^6-25\Rightarrow (m^3)^2-5^2$

It is difference of squares.

$m^7-1\Rightarrow m^7-1^2$

It is not a difference of squares.

Therefore, the correct options are B and C.

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Given the following triangle:

lara [203]

Answer:

A=61, B=74

Step-by-step explanation:

Because all the angles in a triangle add up to 180:

(2x+4) + (2x-9) + x = 180

If you solve that for x, you will get that x=35. Now you just plug in x to the angles A and B.

6 0

2 years ago

Mikki is taking her test and comes across the following question:

kicyunya [14]

Answer:

A. Normal distribution

Step-by-step explanation:

I just did it on usatestprep

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3 years ago

Need help on 15 and 16 PLEASEE!!!

melisa1 [442]

Answer:

Part 15) The next three terms are 5/8,3/4 and 7/8

Part 16) The 37th term is -35.5

Step-by-step explanation:

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant and this constant is called the common difference (d)

Part 15) Find the next three terms of the arithmetic sequence

$\frac{1}{8},\frac{1}{4},\frac{3}{8},\frac{1}{2},...$

$a1=1/8\\ a2=1/4\\ a3=3/8\\ a4=1/2\\ a2-a1=1/4-1/8=1/8\\ a3-a2=3/8-1/4=1/8\\ a4=a3=1/2-3/8=1/8$

The common difference is equal to

d=1/8

Find the next three terms of the arithmetic sequence

Find a5

$a5=a4+d$ -----> $a5=1/2+1/8=5/8$

Find a6

$a6=a5+d$ -----> $a6=5/8+1/8=3/4$

Find a7

$a7=a6+d$ -----> $a7=3/4+1/8=7/8$

therefore

The next three terms are

5/8,3/4 and 7/8

Part 16) what is the 37th term of the arithmetic sequence

$4.1,3,1.9,0.8,...?$

$a1=4.1\\ a2=3\\ a3=1.9\\ a4=0.8$

$a2-a1=3-4.1=-1.1\\ a3-a2=1.9-3=-1.1\\ a4=a3=0.8-1.9=-1.1$

The common difference is equal to

d=-1.1

We can write an Arithmetic Sequence as a rule

$an=a1+d(n-1)$

substitute the values

$an=4.1-1.1(n-1)$

For n=37

substitute

$a37=4.1-1.1(37-1)$

$a37=4.1-1.1(36)$

$a37=-35.5$

4 0

3 years ago

Evaluate the expression for the given value of the variable. n=500 ∛n/4+n/10=?

schepotkina [342]

Answer:

Step-by-step explanation:

To solve the expression, $\sqrt[3]{\frac{n}{4}} + \frac{n}{10}$ substitute n = 500 and simplify according to order of operations.

$\sqrt[3]{\frac{500}{4} } + \frac{500}{10}\\\\\sqrt[3]{125}+50\\ 5+50\\\\55$

4 0

3 years ago

Jason solved the following equation to find the value for x.

Ainat [17]

Plug in 6.5 for x.
-8.5x-3.5x=-78
-8.5(6.5)-3.5(6.5)=-78
-55.25-22.75=-78
-78=-78

5 0

1 year ago