Answer:
definition of perpendicular bisector
Step-by-step explanation:
You need to show the entire problem including the given.
I assume the given info states that
Segment MP is the perpendicular bisector of segment NO.
If that's the case, then the reason for lengths NP and OP being equal is
"definition of perpendicular bisector"
Answer:
39ft²
Step-by-step explanation:
Divide up the Shape
Big rectangle:
a=lw
11*3=33ft
Small rectangle
2*3=6ft
Whole shape:
33+6=39ft²
Answer:
7161 km³
Step-by-step explanation:
28²+b²=32.5²
784+b²=1056.25
b²=1056.25-784
b²=272.25
b=√272.25
b=16.5
1/2x28x16.5x31=7161
Answer:
89
Step-by-step explanation:
Because the data is 1-to-multiple
Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Algebra I</u>
- Terms/Coefficients
- Functions
- Function Notation
- Graphing
<u>Calculus</u>
Area - Integrals
Integration Rule [Reverse Power Rule]:
Integration Rule [Fundamental Theorem of Calculus 1]:
Integration Property [Addition/Subtraction]:
Area of a Region Formula:
Step-by-step explanation:
*Note:
<em>Remember that for the Area of a Region, it is top function minus bottom function.</em>
<em>Also remember that finding area and evaluating are two different things.</em>
<u>Step 1: Define</u>
f(x) = x
g(x) = x³
Bounded (Partitioned) by x-axis
<u>Step 2: Identify Bounds of Integration</u>
<em>Find where the functions intersect (x-values) to determine the bounds of integration.</em>
Simply graph the functions to see where the functions intersect (See Graph Attachment).
Interval: [-1, 1]
1st Integral: [-1, 0]
2nd Integral: [0, 1]
<u>Step 3: Find Area of Region</u>
<em>Integration.</em>
- Substitute in variables [Area of a Region Formula]:
- [Area] Rewrite Integrals [Integration Property - Subtraction]:
- [Area] [Integrals] Integrate [Integration Rule - Reverse Power Rule]:
- [Area] Evaluate [Integration Rule - FTC 1]:
- [Area] [Brackets] Add/Subtract:
- [Area] Add:
Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Area Under the Curve - Area of a Region (Integration)
Book: College Calculus 10e