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tino4ka555 [31]
3 years ago
11

Can you figure this out please..

Mathematics
1 answer:
Naddik [55]3 years ago
3 0

Answer:

n = 5, 6, 7

Step-by-step explanation:

Change the fractions into fractions with a denominator of 16

Multiply numerator/denominator by 4

\frac{1}{4} = \frac{4(1)}{4(4)} = \frac{4}{16}

Multiply the numerator/denominator by 8

\frac{1}{2} = \frac{8(1)}{8(2)} = \frac{8}{16}

Thus \frac{n}{16} is between \frac{4}{16} and \frac{8}{16}

Meaning it can be any of

\frac{5}{16}, \frac{6}{16}, \frac{7}{16} with n = 5, 6, 7

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What is the sum of 20x^2-10x-30
ivann1987 [24]

Answer:

The sum of the roots is 0.5

Step-by-step explanation:

<u><em>The correct question is</em></u>

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

ax^{2} +bx+c=0

The sum of the roots is equal to

-\frac{b} {a}

in this problem we have

20x^{2} -10x-30=0  

so

a=20\\b=-10\\c=-30

substitute

-\frac{(-10)} {20}=0.5

<u><em>Verify</em></u>

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

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substitute

x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}

x=\frac{10\pm\sqrt{2,500}} {40}

x=\frac{10\pm50} {40}

x=\frac{10+50} {40}=1.5

x=\frac{10-50} {40}=-1

The roots are x=-1 and x=1.5

The sum of the roots are

-1+1.5=0.5 ----> is ok

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