Question

O:250 degrees A In this figure, mzBDA = • and m2BCA = Please

Answer 1

Answer:

∠ BDA = 55° , ∠ BCA = 70°

Step-by-step explanation:

∠ BOA = 360° - 250° = 110° ( angles round a point )

The central angle is twice the angle on the circle, subtended on the same arc

∠ BDA = $\frac{1}{2}$ ∠ BOA = $\frac{1}{2}$ × 110° = 55°

OBCA is a tangent kite

Opposite angles sum to 180° , then

∠ BCA = 180° - ∠ BOA = 180° - 110° = 70°