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Dafna1 [17]
3 years ago
8

Question 8 Multiple Choice Worth 1 points)

Mathematics
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

Option B.

Step-by-step explanation:

Note: The function f(x) is not in correct format it must be f(x)=3^x.

It is given that two different plants that grow each month at different rates are represented by the functions f(x) and g(x).

Let as consider the two functions,

f(x)=3^x

g(x)=5x+12

Now, table of values is

Month(x)        f(x)=3^x           g(x)=5x+12

    1                      3                          17

    2                     9                         22

    3                     27                        27

    4                     81                        32

From the above table it is clear that in first and second month the height of the f(x) plant is less than of g(x).

In month 3, heights are equal.

In month 4, height of the f(x) plant exceed that of the g(x) plant.

Therefore, the correct option is B.

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Answer:

D

Step-by-step explanation:

7 0
2 years ago
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:20 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:20 the acce
storchak [24]

Answer:

The correct answer will be "60 min/hour".

Step-by-step explanation:

At time 2:00 PM

A car reads = 30 mi/h

At time 2:20 PM

A car reads = 50 mi/h

Now,

At time 2:00 PM

t = 0

At time 2:20 PM

t = \frac{1}{3}

v(0)=30

v(\frac{1}{3})=50

For MVT,

v'(c)=\frac{v(\frac{1}{3} -v(0))}{(\frac{1}{3} )}

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5 0
3 years ago
Is 7/8 the right answer
kari74 [83]
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6 0
3 years ago
Read 2 more answers
PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!
Nookie1986 [14]

Answer:

\large\boxed{y=\dfrac{1}{4}x^2-x-4}

Step-by-step explanation:

The equation of a parabola in vertex form:

y=a(x-h)^2+k

<em>(h, k)</em><em> - vertex</em>

The focus is

\left(h,\ k+\dfrac{1}{4a}\right)

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of <em>a</em> using k+\dfrac{1}{4a}

<em>k = -5</em>

-5+\dfrac{1}{4a}=-4        <em>add 5 to both sides</em>

\dfrac{1}{4a}=1           <em>multiply both sides by 4</em>

4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4

\dfrac{1}{a}=4\to a=\dfrac{1}{4}

Substitute

a=\dfrac{1}{4},\ h=2,\ k=-5

to the vertex form of an equation of a parabola:

y=\dfrac{1}{4}(x-2)^2-5

The standard form:

y=ax^2+bx+c

Convert using

(a-b)^2=a^2-2ab+b^2

y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5

<em>use the distributive property: a(b+c)=ab+ac</em>

y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4

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3 years ago
Help i need Help im struggling ​
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Answer:

c.2,400 I think is c. nose you

Step-by-step explanation:

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