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3 years ago

What is the vertex of this function f(x)=x^2+12x

Mathematics

1 answer:

tankabanditka [31]3 years ago

4 0

Answer:

(-6, 36)

Step-by-step explanation:

The standard form: ax^2 + bx + c

In this case:

a is 1

b is 12

c is 0

Calculate -b / 2a. This is the x-coordinate of the vertex.

To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y. This is the y-coordinate of the vertex.

-12 / ( 2 x 1 )

-12 / 2

-6

You log -6 in the function

f(x) = x^2 + 12x

f(-6) = (-6)^2 + 12(-6)

= 36 + (-72)

= 36 - 72

= 36

I hope this

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4 years ago

Given the expression: 3x10 − 48x2

BartSMP [9]

Factorization involves representing an expression with smaller terms.

When the greatest common factor is factored out, the equivalent expression is: $3x^2(x^8 - 16)$ .
The complete factored expression is: $3x^2(x^4 - 4)(x^4 + 4)$

The expression is given as:

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The GCF of $3x^{10}$ and $48x^2$ is $3x^2$ .

So, we have:

$3x^{10} -48x^2 = 3x^2 \times x^8 - 3x^2 \times 16$

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$3x^{10} -48x^2 = 3x^2(x^8 - 16)$

To factorize the expression completely, we express $x^8$ and $16$ as squares.

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$3x^{10} -48x^2 = 3x^2((x^4)^2 - 4^2)$

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Read more about factorization at:

brainly.com/question/19386208

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4 years ago

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Zolol [24]

Answer:

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Step-by-step explanation:

A critical point is a point where the slope is zero or undefined. On this graph, every marked point except (-5, 0) is a critical point.

Additional comment

Critical points will be found at local extreme values, places where the tangent is vertical, and places where the slope has a discontinuity (such as (2, 10) and possibly (5, 0)).

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