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Scrat [10]
3 years ago
15

Irene bought 9/16 pounds of wheat flour and for 16 pound of rice flour to use in a bread recipe how much flour did Irene buy in

all
Mathematics
1 answer:
laiz [17]3 years ago
6 0
Can you explain more
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Bill is making accessories for the soccer team. He uses 611.66 inches of fabric on headbands for 31 players and 3 coaches. He al
Sliva [168]

Answer:

26.8 inches of fabrics was used on headband and wristband for each player

Step-by-step explanation:

Headbands for 31 players and 3 couches = 611.66 inches of fabric

Total number of people = 31 players + 3 couches

= 31 + 3

= 34 people

Fabrics per person's headbands = Total inches of fabrics for headbands / total number of people

= 611.66 inches of fabric / 34 people

= 17.99 inches of fabrics per person

Wristband for 31 players = 273.11 inches of fabric

Fabric per person's wristband = total inches of fabrics for wristband / number of players

= 273.11 inches of fabric / 31

= 8.81 inches per person

How much fabric was used on a headband and wristband for each player?

= Fabrics per person's headbands + Fabric per person's wristband

= 17.99 inches + 8.81 inches

= 26.8 inches of fabrics was used on headband and wristband for each player

4 0
3 years ago
How do you simplify 2/3 divided by 1/3
suter [353]

Answer:

2

Step-by-step explanation:

Solve. To do so, change the division sign into a multiplication sign, and flip the second fraction:

(2/3)/(1/3) = (2/3) x (3/1)

Multiply across:

(2 * 3)/(3 * 1) = (6)/(3)

Simplify:

6/3 = 2

2 is your answer.

~

8 0
3 years ago
g A researcher wants to construct a 95% confidence interval for the proportion of children aged 8-10 living in Atlanta who own a
Helga [31]

Answer:

The sample size needed is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.

We have to find n, for which M = 0.02.

There is no estimate of p available, so we use \pi = 0.5

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.02\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.02}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.02})^{2}

n = 2401

The sample size needed is 2401.

7 0
3 years ago
Read 2 more answers
Marta's dog just had six puppies. Four are female (F), and two are male (M). One of the males is brown. Two of the females are b
kondaur [170]
Male is 66% brown is 50% both is 58% and there are two male puppies
8 0
3 years ago
Read 2 more answers
Find the volume and surface area of this triangular prism. 12 cm 13 cm 18 cm and 5 cm ​
Ipatiy [6.2K]
⇒ s = a+b+c2=5+12+132 a + b + c 2 = 5 + 12 + 13 2 = 15 cm.
Area of the base = √s(s−a)(s−b)(s−c)
= √15×10×3×2 15 × 10 × 3 × 2 cm2 = 30 cm2
3 0
2 years ago
Read 2 more answers
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