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3 years ago

Help gai I need help its a math

Mathematics

1 answer:

dem82 [27]3 years ago

6 0

Answer:

Step-by-step explanation:

Rewriting in slope-intercept form.

x - 2y = 0

Add -x on both sides.

- 2y = 0 - x

Divide both sides by -2.

y = 0/-2 - x/-2

y = 0 - - 1/2x

y = 0 + 1/2x

y = 1/2x + 0

The slope is 1/2, the y-intercept is at (0, 0).

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My name is Ann [436]

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3 years ago

a map has a scale of 1.5 inches = 9 miles. On the map, two towns are 4 inches apart. What is the distance, in miles between the

Oksanka [162]

Answer:

Step-by-step explanation:

i multpliy 9x4=36

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3 years ago

A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq

oksano4ka [1.4K]

Answer:

$Lower = 231.134- 3.098=228.036$

$Upper = 231.134+ 3.098=234.232$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case we know that the 95% confidence interval is given by:

$\bar X=\frac{233.002 +229.266}{2}= 231.134$

And the margin of error is given by:

$ME = \frac{233.002 -229.266}{2}= 1.868$

And the margin of error is given by:

$ME= t_{\alpha/2} \frac{s}{\sqrt{n}}$

The degrees of freedom are given by:

$df = n-1 = 5-1=4$

And the critical value for 95% of confidence is $t_{\alpha/2}= 2.776$

So then we can find the deviation like this:

$s = \frac{ME \sqrt{n}}{t_{\alpha/2}}$

$s = \frac{1.868* \sqrt{5}}{2.776}= 1.506$

And for the 99% confidence the critical value is: $t_{\alpha/2}= 4.604$

And the margin of error would be:

$ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098$

And the interval is given by:

$Lower = 231.134- 3.098=228.036$

$Upper = 231.134+ 3.098=234.232$

6 0

3 years ago

Factorise: a^2 + 8a - 20

REY [17]

Which two numbers add up to 88 and multiply to −20?
−2 and 10

Rewrite the expression using the above:

Answer:
(a−2)(a+10)

6 0

3 years ago

Read 2 more answers

When sample size increases Group of answer choices

Olenka [21]

Answer:

Option A)

Confidence interval decreases

Step-by-step explanation:

If we increase the sample size, then,

The standard error of the interval decrease.
If the standard error increase, the margin of error of the interval decrease.
If the margin of error decreases, the width of the confidence level decreases, hence, the confidence interval become narrower.

Thus, the correct answer is

Option A)

Confidence interval decreases

3 0

3 years ago