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Maurinko [17]
2 years ago
12

three different are rung at intervals of 36 minutes 40 minutes and 48 minutes if they were rung together at 9 a.m. at what time

would they be rung together again?​
Mathematics
2 answers:
Lena [83]2 years ago
6 0

To find the time in which all the bells ring together, we need to find the LCM of 36,40,48.

Prime factorization of 36=2×2×3×3

Prime factorization of 40=2×2×2×5

Prime factorization of 48=2×2×2×2×3

Hence, LCM of 36,40,48=2×2×2×2×3×3×5=720 seconds.

 

720seconds=  

60

720

​

minutes=12minutes

Hence, all the bells will ring together after 12 mi

fiasKO [112]2 years ago
6 0

Answer:

9pm or 12 hours from 9am.

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-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{x = 6}

-------------------------------------------------------------------------------------------------------------

Given:  \textsf{The image provided with 2 angles and one side}

Find:  \textsf{Solve for the unknown side of x}

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<u>Plug in the values</u>

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<u>Multiply both sides by x</u>

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<u>Divide both sides by sin(30)</u>

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<u>Simplify</u>

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