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2 years ago

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!! I NEED TO FINISH THESE QUESTIONS BEFORE MIDNIGHT TONIGHT.

Mathematics

2 answers:

Westkost [7]2 years ago

7 0

Answer:

The answer to your question is QS = 5

Step-by-step explanation:

Data

hypotenuse = RQ = 8

angle = 39°

Opposite side = QS = ?

To solve this problem use trigonometric functions. The trigonometric function that relates the opposite side to hypotenuse is sine.

sin α = $\frac{opposite side}{hypotenuse}$

Solve for opposite side

Opposite side = hypotenuse x sin α

Substitution

Opposite side = 8 sin 39

Simplification

Opposite side = 8(0.63)

Result

Opposite side = 5.0

Levart [38]2 years ago

6 0

Answer: QS= 4.93

Step-by-step explanation: because they’re asking you to find QS which is opposite to your angle 39and we have the hypotenuse so we can use sine(39)=x/8.

Sin(39)=x/8

Multiply eight both side

8(sin(39))=x

4.93=x

X=4.93

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I need help ASAP. Thank you :)

kvasek [131]

m∠FDE = 52°

Solution:

Given data:

DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°

Sum of the adjacent angles in a straight line = 180°

m∠ABF + m∠CBF = 180°

116° + m∠CBF = 180°

m∠CBF = 64°

If CD || BE, then CD || BF.

Hence CD || BE and BE || FD.

Therefore BFCD is a parallelogam.

In parallelogram, Adjacent angles form a linear pair.

m∠CBF + m∠BFD = 180°

64° + m∠BFD = 180°

m∠BFD = 116°

Sum of the adjacent angles in a straight line = 180°

m∠BFD + m∠DFE = 180°

116° + m∠DFE = 180°

m∠DFE = 64°

we know that DE ≅ DF.

In triangle, angles opposite to equal sides are equal.

m∠DFE = m∠DEF

m∠DEF = 64°

sum of all the angles of a triangle = 180°

m∠DFE + m∠DEF + m∠FDE = 180°

64° + 64° + m∠FDE = 180°

m∠FDE = 52°

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2 years ago

Here is a picture of a cube, and the net of this cube. What is the surface area of this cube? Enter your answer in the box. ft²

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In right ∆ABC, m B = 90°, m C = 40°, and BC = 10. What are the other two side lengths of the triangle?

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Describe three transformation where the image and preimage have the same size and shape

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Step-by-step explanation:

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A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

2 years ago