Answer:1.69*10^12 J
Step-by-step explanation:
From figure above, using triangle ratio
485/755.5=y/l. Cross multiplying 485l=755.5y Divide via 485) hence l= 755.5y/485
Consider a slice volume Vslice= (755.5y/485)^2∆y; recall density =150lb/ft^3
Force slice = 150*755.5^2.y^2.∆y/485^2
From figure 2 in the attachment work done for elementary sclice 
Wslice= 150.755.5^2.y^2.∆y.(485-y)/485^2
= (150*755.5^2*y^2)(485-y)∆y/485
To calculate the total work we integrate from y=0 to y= 485
Ie W=[ integral of 150*755.5^2 *y^2(485-y)dy/485] at y=0 and y= 485
Integrating the above 
W= 150*755.5^2/485[485*y^3/3-y^4/4] at y= 0 and y=485 
W= 150*755.5^2/485(485*485^3/3-484^4/4)-(485.0^3/3-0^4/4)
Work done 1.69*10^12joules
 
        
             
        
        
        
Answer:
A  
Step-by-step explanation:
 
        
             
        
        
        
Answer:
237?
Step-by-step explanation:
 
        
                    
             
        
        
        
Since both values are positive, it is in quadrant 1
        
             
        
        
        
Answer:
D.
Step-by-step explanation:
None of the above because I believe that it is <em>points</em>