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Serjik [45]
3 years ago
8

For a sale, a store decreases it's prices on all items by 25%. An item that cost $120-0.25($120).what is a another expression fo

r the sale price ?
Mathematics
1 answer:
Butoxors [25]3 years ago
7 0
$120x.25= 30$ <-- the 25% off

$120-$30= $90
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What value is equivalent to 34 − 23⋅ (5 − 2) − 60 ?
xxMikexx [17]

Answer:

68-46 x (10-4)-120

Step-by-step explanation:

3 0
3 years ago
Round off 7613.86 to 3s.f​
solong [7]

Answer:

7613.86 = 7610.00

round off to 3s.f

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4 0
4 years ago
Read 2 more answers
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 30,393 miles, with a standard
Pie

Answer:

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem:

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 30393, \sigma = 2876, n = 37, s = \frac{2876}{\sqrt{37}} = 472.81

What is the probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

This probability is the pvalue of Z when X = 30393 + 339 = 30732 subtracted by the pvalue of Z when X = 30393 - 339 = 30054. So

X = 30732

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{30732 - 30393}{472.81}

Z = 0.72

Z = 0.72 has a pvalue of 0.7642.

X = 30054

Z = \frac{X - \mu}{s}

Z = \frac{30054 - 30393}{472.81}

Z = -0.72

Z = -0.72 has a pvalue of 0.2358

0.7642 - 0.2358 = 0.5284

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

4 0
4 years ago
Use the estimates to help you choose each correct answer. 14.8(20.7) = Estimate: 15(20) = 300 1.1(9.8) = Estimate: 1(10) = 10 72
lara31 [8.8K]

Answer:

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Step-by-step explanation:

bc i just skipped and it showed me the answers

6 0
4 years ago
Read 2 more answers
Answel
LiRa [457]
22 rides would be needed Explanation: one ride takes 6 kids and there are 130 kids 20 rides would take 120 21 rides would take 126 and since you can’t have kids without a ride and you can’t cut a ride into pieces there must be 22 rides
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3 years ago
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