Answer:
A y = x + 1
Step-by-step explanation:
The line starts at 1 on the y-axis so the u intercept will be 1
You first divide both numbers by 4 to get one quarter which is the unit, and to get the rate, you divide 15 by 4 also. i got the unit rate is 3.75 points oer quarter.
Two triangles are said to be <u>congruent</u> if they have <em>similar</em> properties. Thus the required <u>options</u> to complete the <em>paragraph proof</em> are:
a. angle 1 is <u>congruent</u> to angle 2.
b. <em>alternate</em> angles are <u>congruent</u> if two parallel lines are cut by a <em>transversal</em>.
c.
= 
The <em>similarity property</em> of two or more shapes implies that the <u>shapes</u> are congruent. Thus they have the <em>same</em> properties.
From the given <u>diagram</u> in the question, it can be deduced that
ΔABC ≅ ΔABE (<em>substitution</em> property of equality)
Given that EA is <u>parallel</u> to BD, then:
i. <2 ≅ <3 (<em>corresponding</em> angle property)
ii. <1 ≅ < 4 (<em>alternate</em> angle property)
Thus, the required options to complete the <em>paragraph proof</em> are:
- Angle 1 is <em>congruent</em> to angle 2.
- Alternate angles are <u>congruent</u> if two parallel lines are cut by a <em>transversal</em>.
= 
For more clarifications on the properties of congruent triangles, visit: brainly.com/question/1619927
#SPJ1
Answer:
Only equation 1 and 2 are equal.
Step-by-step explanation:
2 (x + 4)2 = 2
2( x² + 8x+ 16) = 2 Applying the square formula
2x² + 16x+ 32 = 2
2x² + 16x+ 32 -2= 0
2x² + 16x+ 30 = 0
2( x² + 8x+ 15)= 0 Taking 2 as common
x2 + 8x + 15 = 0------------eq 1
x2 + 8x + 15 = 0-------------eq 2
(x − 5)2 = 1
x²-10x+25= 1 Applying the square formula
x²-10x+25- 1= 0
x²-10x+24= 0-------------eq 3
x2 − 10x + 26 = 0 -------------eq 4
3(x − 1)2 + 5 = 0
3( x²-2x+1)+5= 0 Applying the square formula
3x²-6x+3+5= 0
3x²-6x+ 8= 0-------------eq 5
3x2 − 6x + 8 =1
3x2 − 6x + 8 -1=0
3x2 − 6x + 7 =0-------------eq 6
Answer:
2x + 3y + 5z = 9
Step-by-step explanation:
The normal defines all the planes perpendicular to that vector. To isolate to a single plane, just apply the known point.
ax + by + cz = d
2x + 3y + 5z = d
2(1) + 3(-1) + 5(2) = 9