$Q=3x^2+5x-2\\R=2-x^2\\S=2x+5\\\\Q-[R+S]=(3x^2+5x-2)-[(2-x^2)+(2x+5)]\\\\=(3x^2+5x-2)-(2-x^2+2x+5)\\\\=(3x^2+5x-2)-[-x^2+2x+(2+5)]\\\\=(3x^2+5x-2)-(-x^2+2x+7)\\\\=3x^2+5x-2-(-x^2)-2x-7\\\\=3x^2+5x-2+x^2-2x-7\\\\=(3x^2+x^2)+(5x-2x)+(-2-7)\\\\=\boxed{4x^2+3x-9}$

5 0

2 years ago

A lot of 80 bulbs contains 45 defective and 32 non warranty bulbs. One bulb is drawn at random from the lot. What is the probabi

kenny6666 [7]

Step-by-step explanation:

Total bulbs = 80

Probability of defective bulbs = 45/80 = 9/16

Probability of non warranty bulbs = 32/80 = 4/5

5 0

2 years ago

Please help me with this I need it now :)

arsen [322]

Answer:

reverse it x-15=4 do 15+4=x

Step-by-step explanation:

6 0

2 years ago