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3 years ago

Make $5 using 12 coins. You must use at least one of each kind of coin; half-dollars, quarters, and dimes

1 answer:

8 0

If you are allowed to use a nickel then this is it. Otherwise I can’t think of a combination off the top of my head. 7 half dollars, 2 dimes, 1 quarter, 1 nickel

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Find all the real square roots of 0.0625

Fudgin [204]

Answer and workings in the attachment below.

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3 years ago

How do the graphs of f (x) = x 2 and g (x)= 3/4 x 2? relate?

Agata [3.3K]

Answer:

$g(x)$ is a horizontal stretch of $f(x)$ by $\frac{3}{4}$ units.

Step-by-step explanation:

The given functions are;

$f(x)=x^2$

and

$g(x)=\frac{3}{4}x^2$

The parent function is $f(x)=x^2$ .

The function $g(x)=\frac{3}{4}x^2$ is a horizontal stretch of $f(x)=x^2$ by $\frac{3}{4}$ units.

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3 years ago

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Write a rational equation that cannot have a solution at x = 2

balandron [24]

Answer: 5+7=2x

Step-by-step explanation:

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3 years ago

1000 x 1000 = ????????????????

bonufazy [111]

Answer:

1,000,000

Step-by-step explanation:

1000 x 1000 = 1,000,000

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3 years ago

Read 2 more answers

A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th

Valentin [98]

Answer:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=12.8$

The sample deviation calculated $s=4.324 \approx 4.3$

$12.8-4.604\frac{4.324}{\sqrt{5}}=3.896$

$12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704$

So on this case the 99% confidence interval would be given by (3.896;21.704)

Step-by-step explanation:

Data: 10,9,20,13,12

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=12.8$

The sample deviation calculated $s=4.324$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,4)".And we see that $t_{\alpha/2}=4.604$

Now we have everything in order to replace into formula (1):

$12.8-4.604\frac{4.324}{\sqrt{5}}=3.896$

$12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704$

So on this case the 99% confidence interval would be given by (3.896;21.704)

6 0

3 years ago