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balandron [24]
3 years ago
14

Please help me on these using conversion factors. And please include work and tell me which one is greater

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0

Answer: 2m > 6ft, 10kg > 10lb


Step-by-step explanation:

6 ft is 72 inches (12 inches per foot)

2 m is a little over 78 inches (39+ inches per meter)

10kg is 22lb (2.2 lb per kg)


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a coin is tossed, then a letter in the word accomplishment is chosen at random. find the probability of heads, then a vowel
emmasim [6.3K]

Answer:

\frac{5}{52}

Step-by-step explanation:

Coin toss:

Total\ outcome=\{H,T\}\\\\Favourable\ outcome=\{H\}\\\\P(Head)=\frac{Favourable\ outcome}{Number\ of\ total\ outcome}\\\\P(Head)=\frac{1}{2}

Letter Selection:

Number\ of\ total\ outcomes=26\ \ \ \ \ \ \ as\ total\ letters\ are\ 26\\\\Favourable\ outcomes=5\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ as\ there\ are\ 5\ vowels\\\\P(vowel)=\frac{Favourable\ outcomes}{Number\ of\ total\ outcomes}\\\\P(vowel)=\frac{5}{26}

These\ two\ events\ are\ independent.\\\\Hence\ probability\ of\ head\ and\ then\ vowel=\frac{1}{2}\times \frac{5}{26}=\frac{5}{52}

4 0
3 years ago
5 pounds of apples cost $9.95. Find the unit rate.
Anna71 [15]
9.95[divide]5 = $1.99
6 0
3 years ago
Read 2 more answers
What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?​
Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

 Given the equation:

\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}

- Using the Difference of squares formula (a^2-b^2=(a+b)(a-b)) we can simplify the denominator of the right side of the equation:

\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}

- Multiply both sides of the equation by (m+3)(3-m) and simplify:

\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}

- Multiply both sides by m-3:

(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)

- Apply Distributive property and simplify:

(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0

- Divide both sides of the equation by -6:

\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0

- Factor the equation and solve for "m":

(m-3)^2=0\\\\m=3

In order to verify it, you must substitute m=3 into the equation and solve it:

\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}

<em>NO SOLUTION</em>

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Answer:the answer is B

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The profit p in thousands of dollars that a manufacturer makes is a function of the number N of items produced in year and the f
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Step-by-step explanation:

G

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