Given these values f(x)=x^2 -3x-4, g(x)=-2x, h(x)-x^3 Evaluate (f(g(h(x)))
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How many times does 24 go into 7?
7 × 1 = 7
7 × 2 = 14
7 × 3 = 21
7 × 4 = 28
7 goes into 24 only three times, leaving three remainder. So you would write it like this: 3
. 7 goes into 24 three times, there is three left over as remainder, and the denominator from before is 7. Thus the answer.
I do hope this helped :))
7 × 1 = 7
7 × 2 = 14
7 × 3 = 21
7 × 4 = 28
7 goes into 24 only three times, leaving three remainder. So you would write it like this: 3
I do hope this helped :))