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3 years ago

5

Given that the measurement is in centimeters, find the area of the circle to the nearest tenth. (Use 3.14 for π)

1 answer:

kvv77 [185]3 years ago

7 0

Answer:

Option D) 254.3 cm2

Step-by-step explanation:

we know that

The area of a circle is equal to

$A=\pi r^{2}$

we have

$r=9\ cm$

substitute

$A=(3.14)(9)^{2}=254.3\ cm^2$

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Jerome found the lengths of each side of triangle QRS as shown, but did not simplify his answers. Simplify the lengths of each s

Margaret [11]

Answer:

$QR = 6.0033$

$QS = 8.22$

$RS = 6.0033$

QRS is isosceles

Step-by-step explanation:

Given

See attachment for complete question

From the attachment, we have the following parameters $QR = \sqrt{(-3-0)^2+(-5.2-0)^2}$

$QR = \sqrt{9+27.04}$

$QS = \sqrt{(-3-5)^2+(-5.2-(-3.322))^2}$

$QS = \sqrt{64+3.53} = \sqrt{67.53$

$RS = \sqrt{(0-5)^2 + (0 - (-3.322))^2}$

$RS = \sqrt{(25 + 11.04}$

Solving further, we have:

$QR = \sqrt{9+27.04}$

$QR = \sqrt{36.04}$

$QR = 6.0033$

$QS = \sqrt{64+3.53} = \sqrt{67.53}$

$QS = 8.22$

$RS = \sqrt{25 + 11.04}$

$RS = \sqrt{36.04}$

$RS = 6.0033$

From the calculations;

$RS = QR = 6.0033$

<em>This means that: QRS is isosceles</em>

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