Question

I ONLY GOT ONE SHOT SO PLS HELP, IM STUPID! ANSWER IF YOU KNOW IT. OR AT LEAST TAKE A LOOK!!!!!!!! ( 2 QUESTIONS)

Answer 1

Answer:

Part 1) The width of the pad is $1\ m$

Part 2) The solutions are

$x=\frac{5(+)\sqrt{97}} {4}$  and $x=\frac{5(-)\sqrt{97}} {4}$

Step-by-step explanation:

Part 1)

Let

x----> the width of the pad

we know that

$(15+2x)(18+2x)=340$

Solve for x

$270+30x+36x+4x^{2} =340\\ \\4x^{2}+66x-70=0$

Solve the quadratic equation by graphing

The solution is $x=1\ m$

see the attached figure

Part 2) we have

$2x^{2} -5x-9=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^{2} -5x-9=0$  

so

$a=2\\b=-5\\c=-9$

substitute in the formula

$x=\frac{5(+/-)\sqrt{-5^{2}-4(2)(-9)}} {2(2)}$

$x=\frac{5(+/-)\sqrt{97}} {4}$

$x=\frac{5(+)\sqrt{97}} {4}$

$x=\frac{5(-)\sqrt{97}} {4}$