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3 years ago

Need help finding out something, refer to picture

Mathematics

2 answers:

Alja [10]3 years ago

8 0

Answer:

He made a mistake in the second line.

Step-by-step explanation:

He factored out x out of 6-2x and 5+4x, which is not possible because there is not an x in both 6 and 5.

Klio2033 [76]3 years ago

7 0

No x I n 6 ddmrmkebw edd dndnd

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What is the answer to -2+(-20)

Nostrana [21]

-2+(-20)
-2 - 20
-22
+-= -

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3 years ago

Which statement best describes how to determine whether f(x) = x4 – x3 is an even function?

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For an even function f(x) = f(-x)

So its option A

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4 years ago

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Use elimination to solve<br> 2x+3y=4<br> 4x+6y=-5

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There is no solution to the problem because it is parallel.

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3 years ago

Show the work for INVERSE, thank you. I got 17 but I did it wrong because it has to be 7

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12 - x = 5

Subtract 12 from both sides

12 - 12 - x = 5 - 12

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4 years ago

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Approximate to the nearest tenth the real zeros of f(x)=-5<img src="https://tex.z-dn.net/?f=x%5E%7B3%7D" id="TexFormula1" title=

Vera_Pavlovna [14]

To the nearest tenth the zeroes are:
$x=-0.2, x=-0.7 \:and\: x=2.7$

EXPLANATION

$f(x)=-5x^3+9x^2+12x+2$

The constant term is 2, and the coefficient of the highest degree is -5 so test all rational factors of

$-\frac{2}{5}$

These are;

$\frac{1}{5},\frac{2}{5},-\frac{1}{5}, -\frac{2}{5}$

$f(-\frac{1}{5})=-5(-\frac{1}{5})^3++9( -\frac{1}{5})^2+12( -\frac{1}{5})+2$

$f(-\frac{1}{5})=\frac{5}{125}+\frac{9}{25}-(\frac{12}{5})+2$

$f(-\frac{1}{5})=\frac{5+45-300+250}{125}=\frac{0}{125}=0$

Good for us the very first one is a root. Therefore,

$x=-\frac{1}{5}$

is a root. These also means that

$(5x+1)$

is a factor. Therefore we perform long division to find the other factors as follows.

We can now factor the polynomial as,

$f(x)=-(5x+1)(x^2-2x-2)$

$f(x)=-(5x+1)(x^2-2x-2)=0$

This implies that,

$-(5x+1)=0$

Which gives us

$x=-\frac{1}{5}=-0.2$

Or

$x^2-2x-2=0$

$\Rightarrow x^2-2x=2$

We complete the square to obtain,

$(x-1)^2=2+1$

$\Rightarrow (x-1)^2=3$

Taking square root of both sides gives;

$\Rightarrow x-1=\pm \sqrt{3}$

This implies

$x=1-\sqrt{3}=-0.7$

$x=1+\sqrt{3}=2.7$

7 0

4 years ago