Question

5.19 LAB: Countdown until matching digits Write a program that takes in an integer in the range 20-98 as input. The output is a countdown starting from the integer, and stopping when both output digits are identical. Ex: If the input is:

Answer 1

Answer:

Following are the code to this question:

x = int(input())#defining a variable x for user input value  

if(x>=20 and x<=98):#defining an if block that checks value is in between 20 to 98  

   while(not(x%10==x//10)):#defining while loop that seprate numbers and checks it is not equal  

       print(x)#print value

       x-=1# decrease value by subtracting 1

   print(x)# print value

else:#defining else block  

   print("The input value must lie in 20-98")#print message

Output:

36

36

35

34

33

Explanation:

• In the above python program code, a variable x is declared, which is used to input the value from the user end.
• In the next step, a conditional statement is used in if block, it checks the input value is lie in 20 to 98, and to check its uses and logic date, if it is false it will goto else section in this, it will print a message.
• If the given value is true, inside if block a while loop is declared, that separately divide the value and check it is identical or not, if it is not identical it will print the value and checks its less value similarly.