Answer:
The value of
is
.
Step-by-step explanation:
We know that the position function is given by

Velocity is defined as the rate of change of position. Therefore,

So, the velocity function is

When a body reaches a vertical velocity of zero, this is the maximum height of the body and then gravity will take over and accelerate the object downward. Thus,

We know that the ball bearing reaches its maximum height 21 seconds after being launched (t = 21 s).
So, the value of
is
.
Answer:
13 cm
Step-by-step explanation:
The diagonal of a rectangle forms a right triangle; where the diagonal is a hypotenuse, and two sides of the rectangle are legs.
Using pythagorean's theorem (
), we can say:

The hypotenuse is equal to 13cm.
-12 x -12 = 144 I’m pretty sure if not then it is something different
Answer:
The 99% confidence interval of the population standard deviation is 1.7047 < σ < 7.485
Step-by-step explanation:
Confidence interval of standard deviation is given as follows;

s =
Where:
= Sample mean
s = Sample standard deviation
n = Sample size = 7
χ = Chi squared value at the given confidence level
= ∑x/n = (62 + 58 + 58 + 56 + 60 +53 + 58)/7 = 57.857
The sample standard deviation s =
= 2.854
The test statistic, derived through computation, = ±3.707
Which gives;


1.7047 < σ < 7.485
The 99% confidence interval of the population standard deviation = 1.7047 < σ < 7.485.