The equation that expresses the relationship between the number of boxes, b and the number or cans, c would be c = 48b. This is because the number or cans shipped would be the dependent variable to the problem as it is dependent on the number or boxes that ship along with. So if one ships 2 boxes then the number of cans that would be shipped would need to match the final output of cans which is 96, and using the equation, c = 49b it does.
c = 48b
96 = 48(2)
96 = 96.
Technically the first option will also be correct but usually the variable in an algebraic expression comes after the coefficient.
The answer would be 10z+1/3+4q
For a problem like this, we have to think logically
we know that 6 * some number in the thousands must equal 25 thousand something. Let's say we put 5 in that first spot, 6 * 5,000 is already 30,000 so that's wrong. If we go one lower, 6 * 4,000 is 24,000 and so now we can include the 287 knowing it will fit.
so 6 * 4287 = 25,722.
all we do now is fill in the blanks to match our answer.
Answer:
<h2>a)
483.6cm²</h2><h2>b)
850.1 cm³</h2>
Step-by-step explanation:
Given the slant height 's' and its radius 'r' to be 15cm and 8cm respectively.
the total surface of the cone A = πrs+πr² and the volume is expressed as
V = 1/3πr²h
For the surface area of the cone;
Given parameters
radius = 8 cm and slant height s = 15 cm
Total surface area A = π(8)(15) + π(8)²
A = 90π+64π
A = 154π
If π = 3.14
A = 154(3.14)
A = 483.56cm²
A = 483.6cm²
Hence the total surface area of the cone to the nearest tenth is 483.6cm²
For the volume of the cone;
V = 1/3πr²h
Using pythagoras theorem to get the height of the cone;
l² = h²+r²
h² = l²-r²
h² = 15²-8²
h² = 225-64
h² = 161
h = √161
h = 12.69cm
V = 1/3π* (8)² * 12.69
V = 1/3π* 64 * 12.69
V = 1/3*3.14* 64 * 12.69
V = 2550.1824/3
V = 850.06 cm³
V = 850.1 cm³
Hence, the volume of the cone is 850.1 cm³ to the nearest tenth.
