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OleMash [197]
4 years ago
6

Mr. Lyons is laying tile for the rectangular floor of a hotel lobby. The floor will be 38 tiles wide and 112 tiles long. He has

a total of 4,400 tiles. Which explains whether or not he has enough tiles for the entire floor?
A. No, he does not have enough tiles. He needs 4,456 tiles, so he needs 56 more.
B. No, he does not have enough tiles. He needs 4,600 tiles, so he needs 200 more.
C. Yes, he has enough tiles. He needs only 4,146 tiles and will have 254 left over. D. Yes, he has enough tiles. He needs only 4,256 tiles a
Mathematics
2 answers:
kati45 [8]4 years ago
8 0

D. Yes, he has enough tiles. He needs only 4,256 tiles and will have 144 left over.

Taya2010 [7]4 years ago
6 0
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How to find the missing angle of this quadrilateral if the other angles are 108 degrees, 99 degrees, and 78 degrees?
DerKrebs [107]
Alll angles in a quadrilateral add to 360

so
missing angle=x
108+99+78+x=360
285+x=360
minus 285 from both sides
x=75


missing angle is 75 degrees
4 0
4 years ago
A group of armed forces personnel were surveyed. The branch of service was recorded in the chart below.
cupoosta [38]
27%
divide one hundred thirty five but the total of five hundred and move the decimal back two places
3 0
3 years ago
Read 2 more answers
Struggling with this one really need help on this one!!
otez555 [7]

Hi

P(C) is first B then C

so P ( B) = 0.4

event C is 0.2 also P( C) = 0.4 x 0.2 = 0.08

8 0
3 years ago
In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0
3 years ago
Simplify. (-5) • (7) - (6) • (-2)
andrew11 [14]
Multiply (-5) and (7) together to get -35
Then multiply (6) and (-2) together to get -12

Finally multiply -35 and -12 together to get 420

So your answer to this is 420

Hope this helped :)
Have a good day
8 0
4 years ago
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