a bag contains 6 red balls,and 4 green balls,and 3 blue balls.if we choose a ball,then another ball without putting the first on
1 answer:
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Answer:
= 8n - 11
Step-by-step explanation:
There is a common difference between consecutive terms in the sequence, that is
5 - (- 3) = 13 - 5 = 21 - 13 = 8
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 3 and d = 8 , thus
= - 3 + 8(n - 1) = - 3 + 8n - 8 = 8n - 11 ← note this is the second option, that is
f(n) = - 3 + 8(n - 1)