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andreev551 [17]
3 years ago
8

Which is bigger -2/3 -2/8

Mathematics
1 answer:
Nataliya [291]3 years ago
7 0

Answer:

-2/8

Step-by-step explanation:

Since both numbers are negative we want to find which ever is closer to 0. -2/8 is -1/4 which is closer to 0 then -2/3 so -2/8 is larger

You might be interested in
Given f(x)=4x+5 and g(x)= x^2+x; find (f∘g)(-5)<br> Please show all steps thank you
Greeley [361]

Answer:

(f\circ g)(-5)=85

Step-by-step explanation:

We are given:

\displaystyle f(x)=4x+5\text{ and } g(x)=x^2+x

And we want to find:

(f\circ g)(-5)

This is equivalent to:

\displaystyle =f(g(-5))

So, we will evaluate g(-5) first, which yields:

\displaystyle g(-5)=(-5)^2+(-5)=25-5=20

So:

=f(g(-5))=f(20)

Then:

\displaystyle f(20)=4(20)+5=80+5=85

Therefore:

(f\circ g)(-5)=85

6 0
3 years ago
Your parents charge a family ski trip of $3000 on a credit card, the simple interest rate is 20%. The charges are paid after 6 m
torisob [31]

Answer:

$300

Step-by-step explanation:

In this question, we are simply asked to calculate the simple interest on $3000, at a rate of 20% paid after 6 months.

We can do this as follows. Mathematically, it should be remembered that:

S.I = PRT/100

In this case, we lost out the individual values as follows:

P = $3000, R = 20% and T = 6 months = 0.5years, S.I = ?

We substitute the parameters into the equation:

S.I = (3000 * 20 * 0.5)/100 = $300

7 0
3 years ago
What's greater 11/16 or 0.688?
KengaRu [80]
11/16..." / " means divide....= 0.6875
0.688

when comparing, if it makes it easier, line ur decimals up and put a zero in any empty spaces...

0.6875
0.6880 (this is the same as 0.688)

so the one that is bigger is : 0.688 <==
8 0
4 years ago
How many half-lives of radon-222 have passed in 11.46 days? If 5.2 × 10−8 g of radon-222 remain in a sealed box after 11.46 days
Svetach [21]

Answer:

(i) Approximately 3 half lifes

(ii) 4.21\times 10^{-7}\text{ g}

Step-by-step explanation:

(i) ∵ The half life of Radon-222 is approximately 3.8 days,

So, the number of half life in 11.46 days = \frac{11.46}{3.8} ≈ 3

(ii) Since, the half life formula is,

N=N_0 (\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

Where,

N_0 = initial quantity,

t = number of periods

t_{\frac{1}{2}} = half life of the quantity,

Given,

N = 5.2\times 10^{-8}\text{ g}

t = 11.46 days,

t_{\frac{1}{2}} = 3.8\text{ days}

\implies 5.2\times 10^{-8}=N_0 (\frac{1}{2})^\frac{11.46}{3.8}

\implies N_0=2^{\frac{11.46}{3.8}}\times 5.2\times 10^{-8}\approx 4.21\times 10^{-7}\text{ g}

7 0
4 years ago
in a circle a 60 degree sector has an area of 25 pie square feet. what is the circumference of he circle?
-BARSIC- [3]
C=2π√150 ft
Or, C≈76.95 ft 

Comment if you want to see how I did this.

8 0
4 years ago
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